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Ugo [173]
3 years ago
11

Consider these compounds:

Chemistry
1 answer:
Liula [17]3 years ago
7 0

Answer:

Without doing any calculations it is possible to determine that silver chloride is more soluble than ACD, and silver chloride is less soluble than ___.

It is not possible to determine whether silver chloride is more or less soluble than B by simply comparing Ksp values.

Explanation:

The Lead (Pb) is a heavy metal and Zinc (Zn) is a transition metal, both combine with the anion phosphate produces heavy complexes very insoluble.

The silver cation (Ag+) is an acid cation which in basic conditions rapidly precipitates as AgOH which is highly insoluble and unstable.

The FeCO3 is a complex with a solubility relatively close between AgCl. The Kps of these two are 3.2x10^{-11} and 1.8x10^{-10} respectively at room temperature.

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Volume of Argon V1 = 5.0 L  
Pressure of Argon P1 = 2 atm 
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We know that (P1 x V1) / T1 = (P2 x V2) / T2  
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. 125g of water has an initial temperature of 25.6°C, and is heated by 50.0g of a metal
Eduardwww [97]

Answer : The specific heat of the metal is, 0.451J/g^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of metal = ?

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of metal = 50.0 g

m_2 = mass of water  = 125 g

T_f = final temperature of mixture = 29.3^oC

T_1 = initial temperature of metal = 115.0^oC

T_2 = initial temperature of water = 25.6^oC

Now put all the given values in the above formula, we get

(50.0g)\times c_1\times (29.3-115.0)^oC=-[(125g)\times 4.18J/g^oC\times (29.3-25.6)^oC]

c_1=0.451J/g^oC

Therefore, the specific heat of the metal is, 0.451J/g^oC

4 0
3 years ago
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