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Mashcka [7]
4 years ago
15

Consider two solutions: one formed by adding 10.0 grams of glucose (C6H12O6) to 1.0 L of water

Chemistry
1 answer:
timofeeve [1]4 years ago
8 0

Answer:

Explanation:

Lowering of vapour pressure of solvent is proportional to number of moles   of solute dissolved in it per litre .

No of moles of glucose dissolved

= mass dissolved / molecular weight of glucose

= 10 / 180

= .055  moles.

No of moles of sucrose dissolved = 10 / 342

= .029 moles.

So reduction in vapour pressure will be lower of  solution dissolving sucrose . It is so because , no of moles of solute dissolved in it is low.  

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Answer:

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3 0
3 years ago
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