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Mashcka [7]
4 years ago
15

Consider two solutions: one formed by adding 10.0 grams of glucose (C6H12O6) to 1.0 L of water

Chemistry
1 answer:
timofeeve [1]4 years ago
8 0

Answer:

Explanation:

Lowering of vapour pressure of solvent is proportional to number of moles   of solute dissolved in it per litre .

No of moles of glucose dissolved

= mass dissolved / molecular weight of glucose

= 10 / 180

= .055  moles.

No of moles of sucrose dissolved = 10 / 342

= .029 moles.

So reduction in vapour pressure will be lower of  solution dissolving sucrose . It is so because , no of moles of solute dissolved in it is low.  

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12. If the total pressure exerted by 3 gases is 45 atm and each individual gas has the
Bumek [7]

Answer:

Partial pressure for each of the three gases, in the mixture is 15 atm

Explanation:

Remember that the total pressure of a mixture, is the sum of partial pressures from the gases contained in the mixture.

Our total pressure = 45 atm

The 3 gases have the same pressure, so we can propose this equation:

3x = 45 atm

where x is the partial pressure for each of the three gases.

x = 45/3 → 15 atm

3 0
4 years ago
If a body of water has high turbidity levels, what can most likely be concluded?
harina [27]
Unsafe to dono because it’s way too high
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Which type of eclipse would you expect to see if the moon passes directly between earth and the sun?
Deffense [45]

C. A total lunar eclipse.

4 0
3 years ago
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Water is an amphoteric substance because it can receive and donate hydrogen ions.
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Answer:

True

Explanation:

The answer is True...

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3 years ago
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El osmio es un metal sólido que tiene una densidad
pentagon [3]

Respuesta:

4.42 × 10⁻⁶ m³

Explicación:

Paso 1: Información provista

  • Densidad del osmio (ρ): 22600 kg/m³
  • Masa de osmio (m): 100 g

Paso 2: Convertir 100 g a kilogramos

Usaremos el factor de conversion 1 kg = 1000 g.

100 g × 1 kg/1000 g = 0.100 kg

Paso 3: Calcular el volumen ocupado por 0.100 kg de osmio

La densidad es una propiedad intensiva, igual al cociente entre la masa y el volumen.

ρ = m/V

V = m/ρ

V = 0.100 kg / (22600 kg/m³) = 4.42 × 10⁻⁶ m³

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3 years ago
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