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DanielleElmas [232]
2 years ago
8

A 25. 00 ml sample of acetic acid containing phenolphthalein indicator is titrated with 0. 1067 m naoh. The solution changes col

or after 30. 07 ml naoh has been added. What is the concentration of the acetic acid before titration?.
Chemistry
1 answer:
sasho [114]2 years ago
7 0

The concentration of acetic acid:

The concentration of the acetic acid before titration is 0.128 M

What is titration?

Titration is a quantitative analytical procedure that works by allowing a known analyte to gradually react with a titrant until an endpoint is reached.

Titration for weak acid and strong base:

Moles of acetic acid =  moles of NaOH

Given:

Concentration of NaOH = 0.1067 M

Volume of NaOH = 30.07 ml = 0.03007 L

Calculation:

So, by using the formula, Concentration = Moles/Volume

Moles of NaOH = concentration x volume = 0.1067 x 0.03007 = 0.0032

Therefore, the moles of acetic acid  = 0.0032 mole

Now, using the formula again for determining the concentration of acetic acid, we get,

Concentration = Moles/Volume

Concentration of acetic acid =  0.0032/0.025 = 0.128M

Learn more about titration here,

brainly.com/question/2728613

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Explanation:

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How many grams of NaF form when .5 mol of HF reacts with excess Na2SiO3?
IgorLugansk [536]

Answer:

5.25g

Explanation:

We'll begin by writing the balanced equation for the reaction. This is shown below:

Na2SiO3 + 8HF → H2SiF6 + 2NaF + 3H2O

From the balanced equation above,

8 moles of HF reacted to produce 2 moles of NaF.

Therefore, 0.5 moles of HF will react to produce = (0.5 x 2)/8 = 0.125 mole of NaF.

Next, we shall convert 0.125 mole of NaF to grams.

This is illustrated below:

Mole of NaF = 0.125 mole

Molar mass of NaF = 23 + 19 = 42g/mol

Mass of NaF =..?

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Mass of NaF = 0.125 x 42

Mass of NaF = 5.25g

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3 years ago
At a certain temperature the rate of this reaction is first order in HI with a rate constant of :0.0632s
Shalnov [3]

Answer : The time taken for the reaction is, 28 s.

Explanation :

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant  = 0.0632

t = time taken for the process  = ?

[A_o] = initial amount or concentration of the reactant  = 1.28 M

[A] = amount or concentration left time 't' = 1.28\times \frac{17}{100}=0.2176M

Now put all the given values in above equation, we get:

0.0632=\frac{2.303}{t}\log\frac{1.28}{0.2176}

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OlgaM077 [116]

Answer:

HI(aq) + H₂O(ℓ) ⟶ H₃O⁺(aq) + I⁻(aq)

Explanation:

The HI donates a proton to the water, converting it to a hydronium ion

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3 0
3 years ago
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