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DanielleElmas [232]
2 years ago
8

A 25. 00 ml sample of acetic acid containing phenolphthalein indicator is titrated with 0. 1067 m naoh. The solution changes col

or after 30. 07 ml naoh has been added. What is the concentration of the acetic acid before titration?.
Chemistry
1 answer:
sasho [114]2 years ago
7 0

The concentration of acetic acid:

The concentration of the acetic acid before titration is 0.128 M

What is titration?

Titration is a quantitative analytical procedure that works by allowing a known analyte to gradually react with a titrant until an endpoint is reached.

Titration for weak acid and strong base:

Moles of acetic acid =  moles of NaOH

Given:

Concentration of NaOH = 0.1067 M

Volume of NaOH = 30.07 ml = 0.03007 L

Calculation:

So, by using the formula, Concentration = Moles/Volume

Moles of NaOH = concentration x volume = 0.1067 x 0.03007 = 0.0032

Therefore, the moles of acetic acid  = 0.0032 mole

Now, using the formula again for determining the concentration of acetic acid, we get,

Concentration = Moles/Volume

Concentration of acetic acid =  0.0032/0.025 = 0.128M

Learn more about titration here,

brainly.com/question/2728613

#SPJ4

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Explanation:

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Initial concentration of cyclohexane =\frac{moles}{Volume}=\frac{0.069}{2.8}=0.025M

The given balanced equilibrium reaction is,

                            cyclohexane  ⇔  methylcyclopentane

Initial conc.                 0.025 M           0

At eqm. conc.       (0.025-x)M       (x) M

The expression for equilibrium constant for this reaction will be,

K= methylcyclopentane / cyclohexane

Now put all the given values in this expression, we get :

0.12=\frac{(x)}{(0.025-x)}

By solving the term 'x', we get :

x =  0.0027

Concentration of cyclohexane at equilibrium = (0.025-x ) M = (0.025-0.0027) M = 0.0223 M

Concentration of methylcyclopentane at equilibrium = (x ) M = (0.0027) M

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A 150.0 mL sample of a 1.50 M solution of CuSO4 is mixed with a 150.0 mL sample of 3.00 M KOH in a coffee cup calorimeter. The t
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