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3 years ago

How does the vegetation surface type affect the amount of runoff

Chemistry

1 answer:

maxonik [38]3 years ago

5 0

Answer:

The type of vegetation a surface does affect the water coming from above to sink in or runoff. 

Explanation:

This is how the vegetation affects the runoff:-

The leaves and stems present in the vegetation do not let the water fall directly on the soil and makes the process rather slow which makes the water to get to the ground slowly and sink in properly inside the soil rather than running off.

If the vegetation present is dense with there was being hairy then also the water would not run out and will get absorbed by the roots letting the soil intact

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Distinguish between monopoly and monopolistic competition

blondinia [14]

Answer:

○MONOPOLY ○

○1▪︎Monopoly is the type of imperfect competition where a seller or producer captures the majority of market share due to lack of substitutes or competitors.○

○2▪︎Nil competition exists as only one seller present in the market.○

○MONOPOLISTIC ○

○1▪︎Monopolistic competition is a type of imperfect competition where many sellers try to capture market share by differentiating their products.○

○2▪︎Very high competition exists as there are many sellers.○

7 0

3 years ago

Magnesium reacts with hydrochloric acid (HCl) as follows. Mg(s) + 2HCl(aq) -->MgCl(2)+H(2)(g) How many milliliters of hydroge

max2010maxim [7]

We are given the number of moles of solid magnesium supplied for the reaction which is 0.02 moles while hydrochloric acid is supplied in excess thus we can say that the reaction proceeds to completion. Calculation is as follows:

0.020 mol Mg ( 1 mol H2 / 1 mol Mg ) = 0.020 mol H2 gas is produced

To convert the number of moles to volume, we use the conditions at STP of 1 mol of a substance is equal to 22.4 L. Thus,

0.020 mol H2 (22.4 L / 1 mol) (1000 mL / 1 L) = 448 mL

5 0

4 years ago

If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?

ICE Princess25 [194]

Answer: The half life of the sample of silver-112 is 3.303 hours.

Explanation:

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

$k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}$

where,

k = rate constant = ?

t = time taken = 1.52 hrs

$[A_o]$ = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

$k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}$

To calculate the half life period of first order reaction, we use the equation:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life period of first order reaction = ?

k = rate constant = $0.2098hr^{-1}$

Putting values in above equation, we get:

$t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs$

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0

3 years ago

How many milliliters of 4.00 m hcl(aq) are required to react with 2.75 g of zn(s)?

Anna007 [38]

25 milliliters are required

7 0

3 years ago

toms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group.

Novosadov [1.4K]

Answer:

Atoms of elements at the top of a group on the periodic table are smaller than the atoms of elements at the bottom of the group. ... The valence electrons of the larger atoms are farther from the nucleus and are easier to remove, so the metals near the bottom are more reactive than those at the top.

8 0

3 years ago