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Vinvika [58]
2 years ago
9

How does the vegetation surface type affect the amount of runoff

Chemistry
1 answer:
maxonik [38]2 years ago
5 0

Answer:

<em>The type of vegetation a surface does affect the </em><em>water coming from above to sink in or runoff. </em>

Explanation:

This is how the vegetation affects the runoff:-

The leaves and stems present in the vegetation do not let the water fall directly on the soil and makes the process rather slow which makes the water to get to the ground slowly and sink in properly inside the soil rather than running off.

If the vegetation present is dense with  there was being hairy then also the water would not run out and will get absorbed by the roots letting the soil intact

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Which statement describes an Arrhenius acid
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If the sample contained 2.0 moles of KClO3 at a temperature of 214.0 °C, determine the mass of the oxygen gas produced in grams
Westkost [7]

Answer : The mass of the oxygen gas produced in grams and the pressure exerted by the gas against the container walls is, 96 grams and 1.78 atm respectively.

Explanation : Given,

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Now we have to calculate the moles of MgO

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2KClO_3\rightarrow 2KCl+3O_2

From the balanced reaction we conclude that

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\text{ Mass of }O_2=\text{ Moles of }O_2\times \text{ Molar mass of }O_2

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Now we have to determine the pressure exerted by the gas against the container walls.

Using ideal gas equation:

PV=nRT\\\\PV=\frac{w}{M}RT\\\\P=\frac{w}{V}\times \frac{RT}{M}\\\\P=\rho\times \frac{RT}{M}

where,

P = pressure of oxygen gas = ?

V = volume of oxygen gas

T = temperature of oxygen gas = 214.0^oC=273+214.0=487K

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M = molar mass of oxygen gas = 32 g/mole

Now put all the given values in the ideal gas equation, we get:

P=1.429g/L\times \frac{(0.0821L.atm/mole.K)\times (487K)}{32g/mol}

P=1.78atm

Thus, the pressure exerted by the gas against the container walls is, 1.78 atm.

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