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marshall27 [118]
3 years ago
6

You place air in a sealed can at standard temperature and pressure STP you double it's absolute temperature

Chemistry
2 answers:
Aloiza [94]3 years ago
6 0
The pressure will triple~! no problem :D
Yuri [45]3 years ago
4 0
The pressure will triple
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The electrical charge of the nucleus is determined by:
elixir [45]
I think it’s electron:)
7 0
2 years ago
Among K, Ca and Ba, which element possess low ionization energy?
deff fn [24]

Among the elements Barium has the lowest Ionization Energy.

<h3>What is Ionization Process ?</h3>

The process by which any neutral atom gets converted into electrically charged by gaining or losing electron is called Ionization Process.

K  is an alkali metal  it has to lose one electron to attain stable electronic configuration of an inert gas

For removing second electron , a stable configuration has to be broken and so will require high amount of energy.

Ca and Ba are alkaline earth metals.

They both have to lose 2 electrons to attain  stable electronic configuration of noble gas.

They have low Iow Ionization Energy as compared to K.

Ca has higher  Ionization Energy as compared to Ba because when we move down the periodic table , The ionization energy decreases.

Hence , Among the elements Barium has the lowest Ionization Energy.

To know more about Ionization Process

brainly.com/question/6638422

#SPJ1

5 0
2 years ago
In a particular redox reaction, no2– is oxidized to no3– and cu2 is reduced to cu . Complete and balance the equation for this r
lianna [129]

Reduction half reaction: Cu²⁺(aq) + 2e⁻ → Cu⁰(s).


Oxidation half reaction: NO₂⁻(aq) + H₂O(l) → NO₃⁻(aq) + 2H⁺(aq) + 2e⁻.  

Balanced chemical reaction:

Cu²⁺(aq) + NO₂⁻(aq) + H₂O(l) → Cu(s) + NO₃⁻(aq) + 2H⁺(aq).

Copper is reduced from oxidation number +2 (Cu²⁺) to oxidation number 0 (Cu) and nitrogen is oxidized from oxidation number +3 (in NO₂⁻) to oxidation number +5 (in NO₃⁻).


8 0
2 years ago
Read 2 more answers
Consider the reaction 2CO * O2 —&gt; 2 CO2 what is the percent yield of carbon dioxide (MW= 44g/mol) of the reaction of 10g of c
Arturiano [62]

Answer:

Y = 62.5%

Explanation:

Hello there!

In this case, for the given chemical reaction whereby carbon dioxide is produced in excess oxygen, it is firstly necessary to calculate the theoretical yield of the former throughout the reacted 10 grams of carbon monoxide:

m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO}  *\frac{44gCO_2}{1molCO_2}\\\\ m_{CO_2}^{theoretical}=16gCO_2

Finally, given the actual yield of the CO2-product, we can calculate the percent yield as shown below:

Y=\frac{10g}{16g} *100\%\\\\Y=62.5\%

Best regards!

8 0
3 years ago
Help please !
AURORKA [14]

Answer:

false

true

true

Explanation:

false - changing the hypothesis to meet your needs is not a good researcher

true - when you can further analyze and explain then you have a successful experiment even if it's not what you expected

true - successful experiments do not end there. they can lead to more in depth questions.

8 0
2 years ago
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