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trasher [3.6K]
3 years ago
15

What is the electron structure of a beryllium ion with a net ionic charge of +2?

Chemistry
2 answers:
yuradex [85]3 years ago
8 0

Answer:

Be²⁺: 1s²

Explanation:

The electron configuration is as follows:

Be: 1s²2s²

Be²⁺: 1s²

Be²⁺ ion has two electrons in the first shell. This is a stable electron configuration. The other stable electron configuration is an octet where there are eight valence electrons.  

The electron configuration of Be²⁺ is the same as that of He (helium). Helium is a noble or inert gas.  

Be²⁺ = He = 1s²

Otrada [13]3 years ago
4 0
It will be the core of the atom surrounded by one electron cloud with two electrons the second electron cloud with the two other electrons will be omitted because those electrons were lost to give it a positive charge. electrons and protons come in equal numbers at most ground states and that is why. For periodic table however the proton count will always be the same count as the electrons.
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Molecules can be dissolved? Why?
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4 0
2 years ago
Read 2 more answers
A. Based on the activation energies and frequency factors, rank the following reactions from fastest to slowest reaction rate, a
deff fn [24]

Answer:

A) E_{a} = 350KJ/mol, E_{a} = 50KJ/mol, E_{a} = 50KJ/mol

     A = 1.5×10^{-7}s^{-1}, A = 1.9×10^{-7} s^{-1}, A=1.5×10^{-7} s^{-1}

B) 4.469

Explanation:

From Arrhenius equation

      K=Ae^{\frac{E_{a} }{RT} }

where; K = Rate of constant

            A = Pre exponetial factor

            E_{a} = Activation Energy

             R = Universal constant

             T = Temperature in Kelvin

Given parameters:

E_{a} =165KJ/mol

T_{1}=505K

T_{2}=525K

R=8.314JK^{-1}mol^{-1}

taking logarithm on both sides of the equation we have;

InK=InA-\frac{E_{a} }{RT}

since we have the rate of two different temperature the equation can be derived as:

In(\frac{K_{2} }{K_{1} } )=\frac{E_{a} }{R}(\frac{1}{T_{1} } -\frac{1}{T_{2} } )

In(\frac{K_{2} }{K_{1} } )=\frac{165000J/mol}{8.314JK^{-1}mol^{-1}  }.(\frac{1}{505} -\frac{1}{525} )

In(\frac{K_{2} }{K_{1} } )= 19846.04×7.544×10^{-5} = 1.497

\frac{K_{2} }{K_{1} } =e^{1.497} = 4.469

 

6 0
3 years ago
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