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trasher [3.6K]
3 years ago
15

What is the electron structure of a beryllium ion with a net ionic charge of +2?

Chemistry
2 answers:
yuradex [85]3 years ago
8 0

Answer:

Be²⁺: 1s²

Explanation:

The electron configuration is as follows:

Be: 1s²2s²

Be²⁺: 1s²

Be²⁺ ion has two electrons in the first shell. This is a stable electron configuration. The other stable electron configuration is an octet where there are eight valence electrons.  

The electron configuration of Be²⁺ is the same as that of He (helium). Helium is a noble or inert gas.  

Be²⁺ = He = 1s²

Otrada [13]3 years ago
4 0
It will be the core of the atom surrounded by one electron cloud with two electrons the second electron cloud with the two other electrons will be omitted because those electrons were lost to give it a positive charge. electrons and protons come in equal numbers at most ground states and that is why. For periodic table however the proton count will always be the same count as the electrons.
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If 5.57 g of Ag2O is sealed in a 75.0-mL tube filled with 760 torr of N2 gas at 28 ∘C, and the tube is heated to 310 ∘C, the Ag2
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Answer: Total pressure = 7293.2 torr or 9.60 atm

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<em>Total pressure = partial pressure of nitrogen + partial pressure of oxygen</em>

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P₁ = 760 torr = 1atm, T₁ = 28∘C = (273+28)K = 301k, P₂ = ?, T₂ = 310∘C =(310+273)K = 583K

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P₂ = 760 * 583 / 301 = 1472.03 torr

The pressure due to Oxygen gas produced is calculated thus:

Balanced equation of the decomposition of Ag₂O at s.t.p. is as follows;

2Ag₂O ----> 4Ag + O₂(g)

2 moles of Ag₂O produces 1 mole of O₂

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molar volume of gas at s.t.p. = 22.4L

2*232g i.e. 464g of Ag₂O produces 22.4L of O₂

5.57g of Ag₂O will produce 5.57g*22.4L/464g = 0.269L or 269mL of O₂

Using the General gas equation  P₁V₁/T₁=P₂V₂/T₂

P₁ = 1atm = 760 torr, V₁ = 269mL, T₁=273K, P₂ = ?, V₂= 75mL, T₂ = 583K

P₂ = P₁V₁T₂/V₂T₁

P₂ = 760*269*583 / 75*273

P₂ = 5821.17 torr

Total pressure = (1472.03 + 5821.17) torr

Total pressure = 7293.2 torr or 9.60 atm

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