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3 years ago

0.71 g Cu equals how many moles

Chemistry

2 answers:

Julli [10]3 years ago

8 0

Answer: 0.011 moles

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 Liters at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

given mass = 0.71 g

Molar mass= 63.5 g

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

$\text{Number of moles}=\frac{0.71g}{63.5g/mol}=0.011moles$

The number of moles is 0.011 moles.

Norma-Jean [14]3 years ago

5 0

The correct answer is 0.011330374846536 Hope this helps ;D

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What is formed when 2 non metals reacts?

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Answer:

A) covalent bond

Explanation:

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3 years ago

Stirring a liquid while you are mixing in another ingredient speeds up the rate of dissolving. Question 13 options: True False

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2 years ago

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In a synthesis reaction, one reactant contains 346 J of chemical energy, and one reactant contains 153 J of chemical energy. The

Eduardwww [97]

Answer:

64J of energy must have been released.

Explanation:

Step 1: Data given

One reactant contains 346 J of chemical energy, the other reactant contains 153 J of chemical energy.

The product contains 435 J of chemical energy.

Step 2:

Since the energy is conserved

Sum of energy of Reactants = Energy of Products

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The energy of the product = 435 J

435 < 499

This means energy must have been lost as heat.

Step 3: Calculate heat released

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64J of energy must have been released.

4 0

3 years ago

For the simple decomposition reactionAB(g)→ A(g) + B(g)Rate =k[AB]2 and k=0.2 L/mol*s . How long will it takefor [AB] to reach 1

mixer [17]

Answer:

6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.

Explanation:

$Rate = k[AB]^2$

The order of the reaction is 2.

Integrated rate law for second order kinetic is:

$\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt$

Where, $[A_0]$ is the initial concentration = 1.50 mol/L

$[A_t]$ is the final concentration = 1/3 of initial concentration = $\frac{1}{3}\times 1.50\ mol/L$ = 0.5 mol/L

Rate constant, k = 0.2 L/mol*s

Applying in the above equation as:-

$\frac{1}{0.5} = \frac{1}{1.50}+0.2t$

$\frac{1}{1.5}+0.2x=\frac{1}{0.5}$

$t = 6.66\ s$

<u>6.66 s will it take for [AB] to reach 1/3 of its initial concentration 1.50 mol/L.</u>

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3 years ago

What is the empirical formula for a compound that is 31.9% potassium, 28.9% chlorine, and 39.2% oxygen?

notsponge [240]

The empirical formula for a compound is KClO3

Explanation
find the moles of each element
moles = % composition/molar mass

molar mass of of potassium =39g/mol ,chlorine = 35.5 g/mol, oxygen =16 g/mol

moles of potassium = 31.9 / 39 = 0.818 moles
moles of chlorine = 28.9/35.5 = 0.814 moles
moles of oxygen = 39.2/ 16 = 2.45 moles

find the mole ratio by dividing with the smallest mole = 0.814 moles

potassium = 0.818/0.814 =1
chlorine = 0.814/0.814 = 1
oxygen = 2.45 /0.814 =3

the empirical formula is therefore = KClO3

7 0

3 years ago