Being frozen, staying a liquid, becoming ice, and becoming a gas (steam)
The anion<span> is also </span>larger than<span> the </span>atom<span> because of </span>electron-electron repulsion<span>. As more </span>electrons are<span> added to the </span>outer shell<span>, and even to </span>higher<span> principle energy levels, the </span>repulsion<span> bewteen the negatively charged particles grows, pushing the </span>shells<span> farther from the nucleus.</span>
The Benzenesulfonic acid does not undergo Friedel-Crafts alkylation because of the deactivation of the compound by the carboxylic group.
<h3>What is the Grignard reagent?</h3>
The Grignard reagent is a compound that contains alkyl magnesium halide.
a) The student will be unsuccessful to prepare a Grignard reagent from 4-bromocyclohexanol because of the -OH group that reacts with the Grignard reagent when formed.
b) The Benzenesulfonic acid does not undergo Friedel-Crafts alkylation because of the deactivation of the compound by the carboxylic group.
c) The compound (2S, 3R)- 2,3-Dibromobutane has a specific rotation, [a]D, 0⁰ because it is a meso compound.
d) This is because, the tertiary alkyl halide is more prone to elimination reaction giving the alkene.
e) This is because, the reaction may be occurring by an SN1 mechanism and the rate determining step is the formation of the carbocation.
Learn more about substitution reaction:brainly.com/question/16811879
#SPJ6
Answer:
The reaction when the Borane (BH3) is add to an alkene and form an alkylborane is shown below.
Explanation:
The boron of the borane does not have extra electron pairs, in this way the double bond of the alkene attacks the boron and the hydrogen belonging to the borane adheres to the carbon that is more substituted, thus forming an alkyl borane.