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BaLLatris [955]
3 years ago
8

A burning splint will burn more vigorously in pure oxygen than in air because ________. a burning splint will burn more vigorous

ly in pure oxygen than in air because ________. nitrogen is a product of combustion and the system reaches equilibrium at a lower temperature oxygen is a catalyst for combustion oxygen is a reactant in combustion and concentration of oxygen is higher in pure oxygen than is in air oxygen is a product of combustion nitrogen is a reactant in combustion and its low concentration in pure oxygen catalyzes the combustion
Chemistry
2 answers:
GrogVix [38]3 years ago
6 0
A burning splint will burn more vigorously in pure oxygen than in air because <span>oxygen is a reactant in combustion and concentration of oxygen is higher in pure oxygen than is in air.
Oxygen concentration in air is approximately 20%, the rest of are nitrogen, carbon dioxide and other gases. Oxygen is oxidazing reactant, that means oxygen give electrons in chemical reactions.
</span>
storchak [24]3 years ago
3 0
<span>A burning splint will burn more vigorously in pure oxygen than in air because  </span><u>oxygen is a reactant in combustion and concentration of oxygen is higher in pure oxygen than is in air</u>.

Explanation:
                    As splints a basically made up of wood and is used in testing oxidizing gases like oxygen

                                     C  +  O₂  →  CO₂  

Also we know that pure oxygen contains 100% oxygen, while that %age of oxygen in air is only 20.95 %. Therefore, combustion reaction will be much faster in pure oxygen due to high concentration of oxygen.
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What volume of 0.550 M KBr solution can you make from 100.0 mL of 2.50 M KBr?
Lostsunrise [7]
M1V1 = M2V2
(2.50)(100.0) = (0.550)V2
V2 = 455mL

You can make 455mL of 0.550M solution from 100.0mL of 2.50M solution.
5 0
3 years ago
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Why is mining for coal a long-term concern?
Delvig [45]

Answer:

B

Explanation:

Coal is a non-renewable resource, so the supply can't produce faster than we can mine it.

8 0
2 years ago
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Since this reaction takes place in acidic solution, H2O(l) and H+(aq) will be involved in the reaction. Places for these species
maxonik [38]

Answer:

The balanced equation is given below:

SO4^2−(aq)+ Sn^2+(aq) + 4H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

The coefficients of the reactants are: 1, 1, 4

The coefficients of the products are: 1, 1, 1

Explanation:

Step 1:

The equation for the reaction. This is given below:

SO4^2−(aq)+ Sn^2+(aq) + –––→ H2SO3(aq)+ Sn^4+(aq) + –––

Step 2:

Inclusion of H+ and H2O into the equation. This is illustrated below:

SO4^2−(aq)+ Sn^2+(aq) + H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

Step 3:

Balancing the equation.

SO4^2−(aq)+ Sn^2+(aq) + H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

The above equation can be balanced as follow:

There are total 4 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 4 in front of H^+ as shown below:

SO4^2−(aq)+ Sn^2+(aq) + 4H^+(aq) → H2SO3(aq)+ Sn^4+(aq) + H2O(l)

Now the equation is balanced.

The coefficients of the reactants are: 1, 1, 4

The coefficients of the products are: 1, 1, 1

5 0
3 years ago
Four gases were combined in a gas cylinder with these partial pressures: 3. 5 atm N2, 2. 8 atm O2, 0. 25 atm Ar, and 0. 15 atm H
aksik [14]

The total pressure of the gas has been 11.9 atm.

The partial pressure has been the pressure exerted by the individual gas in the mixture.

According to the Dalton's law of Partial pressure, the pressure of the gas has been the sum of the partial pressure of each gas in the mixture.

<h3 /><h3>Computation for the pressure of gas</h3>

The given gas has partial pressure of Nitrogen, P_{N_2}=3.5\;\rm atm

The partial pressure of Oxygen, P_{O_2}=8\;\rm atm

The partial pressure of Argon, P_{Ar}=0.25\;\rm atm

The partial pressure of Helium, P_{He}=0.15\;\rm atm

The total pressure, (<em>P</em>) of the gas has been given as:

P=P_{N_2}\;+\;P_{O_2}\;+\;P_{Ar}\;+\;P_{He}\\&#10;P=3.5\;+8\;+\;0.25\;+\;0.15\;\text{atm}\\&#10;P=11.9\;\rm atm

The total pressure of the gas has been 11.9 atm.

Learn more about the vapor pressure, here:

brainly.com/question/25356241

7 0
3 years ago
If a reaction has a ΔG of -136kJ at 110 ºC, will it be spontaneous at this temperature (110 ºC)?
mojhsa [17]

Answer:

The reaction will be spontaneous.

Explanation:

  • The change in free energy (ΔG) is the difference between the heat released during a process and the heat released for the same process occurring in a reversible manner.

  • The sign of ΔG gives an indication for the spontaneity of the reaction:

If ΔG is negative, the reaction is spontaneous.  

If ΔG = zero, the reaction is at equilibrium.

If ΔG is positive, the reaction is non-spontaneous.

7 0
3 years ago
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