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BaLLatris [955]
3 years ago
8

A burning splint will burn more vigorously in pure oxygen than in air because ________. a burning splint will burn more vigorous

ly in pure oxygen than in air because ________. nitrogen is a product of combustion and the system reaches equilibrium at a lower temperature oxygen is a catalyst for combustion oxygen is a reactant in combustion and concentration of oxygen is higher in pure oxygen than is in air oxygen is a product of combustion nitrogen is a reactant in combustion and its low concentration in pure oxygen catalyzes the combustion
Chemistry
2 answers:
GrogVix [38]3 years ago
6 0
A burning splint will burn more vigorously in pure oxygen than in air because <span>oxygen is a reactant in combustion and concentration of oxygen is higher in pure oxygen than is in air.
Oxygen concentration in air is approximately 20%, the rest of are nitrogen, carbon dioxide and other gases. Oxygen is oxidazing reactant, that means oxygen give electrons in chemical reactions.
</span>
storchak [24]3 years ago
3 0
<span>A burning splint will burn more vigorously in pure oxygen than in air because  </span><u>oxygen is a reactant in combustion and concentration of oxygen is higher in pure oxygen than is in air</u>.

Explanation:
                    As splints a basically made up of wood and is used in testing oxidizing gases like oxygen

                                     C  +  O₂  →  CO₂  

Also we know that pure oxygen contains 100% oxygen, while that %age of oxygen in air is only 20.95 %. Therefore, combustion reaction will be much faster in pure oxygen due to high concentration of oxygen.
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If E=mc^2,solve for both m and c. Also, if m=80 and c=0.40 what is the value of E?
Pie

<u><em>Answer:</em></u>

m = \frac{E}{c^2}

c = \sqrt{\frac{E}{m} }

E = 12.8 J

<u><em>Explanation:</em></u>

<u>Part 1: Solving for m</u>

<u>We are given that:</u>

E = mc²

To solve for m, we will need to isolate the m on one side of the equation

This means that we will simply divide both sides by c²

m = \frac{E}{c^2}

<u>Part 2: Solving for c</u>

<u>We are given that:</u>

E = mc²

To solve for c, we will need to isolate the m on one side of the equation

This means that first we will divide both sides by m and then take square root for both sides to get the value of c

c^2 = \frac{E}{m}\\  \\ c=\sqrt{\frac{E}{m}}

<u>Part 3: Solving for E</u>

<u>We are given that:</u>

m = 80 and c = 0.4

<u>To get the value of E, we will simply substitute in the given equation: </u>

E = mc²

E = (80) × (0.4)²

E = 12.8 J

Hope this helps :)

4 0
3 years ago
Declare the volume of the yeast alcohol as a fraction of the total amount of ethanol liquor liquefied alcohol in 30cm of water p
bogdanovich [222]

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5 0
4 years ago
How many liters of water can be formed if 1.65 liters of ethylene are consumed
alexandr1967 [171]
Ethylene Burns in the presence of O₂ to produce CO₂ and H₂O vapors;

                               C₂H₄  +  3 O₂   →   2 CO₂  +  2 H₂O

According to equation, 

22.4 L (1 mole) C₂H₄ reacts completely to produce  =  44.8 L (2 moles) of H₂O

So, 

1.65 L of C₂H₄ on complete reaction will produce  =  X L of H₂O

Solving for X,

                                  X  =  (1.65 L × 44.8 L) ÷ 22.4 L

                                  X  =  3.3 L of H₂O
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irina1246 [14]

Answer:

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Explanation:

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Answer:

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Explanation:

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