All categories

3 years ago

HELP FAST!!! MULTIPLE CHOISE!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Dvinal [7]3 years ago

6 0

Answer: C. 1462

Step-by-step explanation: It is 1462 Kilograms, why? When rounding the 6 in the tens place rounds the 4 up. Which leads to it being 1500 Kilograms. Hope this clears up your problem! :P

liq [111]3 years ago

5 0

letter C

1462 rounds up when looking at the tens place to 1500

You might be interested in

On a coordinate plane, 2 lines intersect at (negative 1, 5). Which appears to be the solution to the system of equations shown i

Doss [256]

(-1, 5) because if you plug in -1 to both equations, you should get 5 from both equations. They also cross at that point, making that the solution.

4 0

2 years ago

Read 2 more answers

WILL MARK BRAINLIEST ANSWER AND EXPLAIN!!--- thank you!!!!

barxatty [35]

Answer:

hmm...i don't know

i got a verryy different answer

Step-by-step explanation:

V = 1/2 (12*8*34)

= 1632 cm^3

8 0

3 years ago

4(3x^2y^4)^3 / (2x^3y^5)^4

tatyana61 [14]

Solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Step-by-step explanation:

We need to Solve the expression: $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

Solving:

$\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$

$=\frac{4(3^3x^6y^{12})}{(2^4x^{12}y^{20})}\\=\frac{4(27x^6y^{12})}{(16x^{12}y^{20})}\\=\frac{108x^6y^{12}}{16x^{12}y^{20}}$

Applying exponent rule: $\frac{x^a}{x^b}=x^{a-b}$

$=\frac{108x^{6-12}y^{12-20}}{16}\\=\frac{27x^{-6}y^{-8}}{4}$

Another exponent rule says: $x^{-a}=\frac{1}{x^a}=$

$=\frac{27}{4x^{6}y^{8}}$

So, solving the expressions $\frac{4(3x^2y^4)^3}{(2x^3y^5)^4}$ we get $\frac{27}{4x^{6}y^{8}}$

Keywords: Solving Exponents

Learn more about Solving Exponents at:

#learnwithBrainly

8 0

2 years ago

What is a number between 7.833 and 7.834

dalvyx [7]

7.8335 is a number between 7.833 and 8.834

3 0

3 years ago

Read 2 more answers

12) Domain<br> Range<br> Function?<br> -2

Kisachek [45]

Answer: The domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that f takes. (In grammar school, you probably called the domain the replacement set and the range the solution set.

Step-by-step explanation:

7 0

3 years ago