Hello,
To start off, Your answer is Refraction.Refraction is always accompanied by a wavelength. So that is why the wave moves from one medium to another.
Hope this helps
Answer:
9.67 A
Explanation:
We want the magnetic force on the wire to be equal to the weight of a student of mass m=75 kg. The magnetic force on the wire is given by
![F=ILB sin \theta](https://tex.z-dn.net/?f=F%3DILB%20sin%20%5Ctheta)
where
I is the current in the wire
L = 2.0 m is the length of the wire
B = 38 T is the magnetic field
is the angle between the direction of B and L
While the weight of the student is
![W=mg=(75 kg)(9.8 m/s^2)=735 N](https://tex.z-dn.net/?f=W%3Dmg%3D%2875%20kg%29%289.8%20m%2Fs%5E2%29%3D735%20N)
where g=9.8 m/s^2 is the acceleration due to gravity.
The problem can be solved by equalizing the two forces: W=F. So we can write
![ILB sin \theta=W](https://tex.z-dn.net/?f=ILB%20sin%20%5Ctheta%3DW)
And solving for I, the current, we find
![I=\frac{W}{BLsin\theta}=\frac{735 N}{(38 T)(2.0 m)(sin 90^{\circ})}=9.67 A](https://tex.z-dn.net/?f=I%3D%5Cfrac%7BW%7D%7BBLsin%5Ctheta%7D%3D%5Cfrac%7B735%20N%7D%7B%2838%20T%29%282.0%20m%29%28sin%2090%5E%7B%5Ccirc%7D%29%7D%3D9.67%20A)
Answer:
R₂ / R₁ = D / L
Explanation:
The resistance of a metal is
R = ρ L / A
Where ρ is the resistivity of aluminum, L is the length of the resistance and A its cross section
We apply this formal to both configurations
Small face measurements (W W)
The length is
L = W
Area
A = W W = W²
R₁ = ρ W / W² = ρ / W
Large face measurements (D L)
Length L = D= 2W
Area A = W L
R₂ = ρ D / WL = ρ 2W / W L = 2 ρ/L
The relationship is
R₂ / R₁ = 2W²/L