A=3 if the question is 8a divided by 46= 92 I think just check with a caclulator bacuae in not shure
The answer is A. Humid Subtropical
The appropriate hypothesis test for this question is the two proportions test. As the name implies, it is often used to compare existing percentages between two groups. The raw data behind the percentages must be available as the sample size becomes crucially important in determining the test statistics.
The test statistic of the two-proportion test is the Z value. When the sample becomes very large, the Z value is governed under a normal function and is commonly known as the standardized Z value
Sound intensity is inversely proportional to the square of the distance between the source and the receiver.
That is
I = k/r^2
where
k = constant
r = radius
When r=1, the intensity is I₁ = k/1 = k
When r=3, the intensity I₂ = k/3² = k/9
Therefore
I₂ = I₁ /9
In decibels,
I = 10 log₁₀(I/I₀)
where I₀ = reference intensity
When r=1,
10 log₁₀ (I₁/I₀) = 270
When r =3,
10 log₁₀ (I₂/I₀) = 10 log₁₀ [(I₂/I₁)*(I₁/I₀)]
= 10 log₁₀ [(1/9)*(I₁/I₀)]
= 10 log₁₀(1/9) + 270
= 260.5
Answer: 260.5 dB (nearest tenth)
Answer:
Length of the string = 0.24 m
Explanation:
The frequency (f) of vibration of stringed instruments is related to the Tension (T) in the spring by the relation
fₙ = (n/2L)√(T/μ)
where n = 1,2,3,4...
For third harmonic frequency, n = 3
L = length of the string = ?
T = tension in the string = 2.3 N
μ = linear density = 4.6 × 10⁻³ kg/m
f = frequency = 140 Hz
L = (n/2f)√(T/μ)
L = (3/(2×140))√(2.3/0.0046) = 0.40 m
