The patch area in square kilometers is 1.59*10⁻⁹ km₂
Why?
This is an unit conversion problem. We have to convert from cm² to km². We can do that by knowing that there are 100 cm in 1 m, and 1000 m in 1 km, so 100000 cm=1km. Knowing that we can apply the following conversion factor:
![15.9 cm^{2} * (\frac{1 km}{100000 cm} )^{2}=0.00000000159 km^{2}](https://tex.z-dn.net/?f=15.9%20cm%5E%7B2%7D%20%2A%20%28%5Cfrac%7B1%20km%7D%7B100000%20cm%7D%20%29%5E%7B2%7D%3D0.00000000159%20km%5E%7B2%7D)
Now to convert this value to scientific notation, we have to move the decimal point to the right until we get a whole number, and the exponent of the number 10 is going to be the number of spaces we moved to the right (negative), so the final answer is:
![0.00000000159 km^{2}=1.59*10^{-9} km^{2}](https://tex.z-dn.net/?f=0.00000000159%20km%5E%7B2%7D%3D1.59%2A10%5E%7B-9%7D%20km%5E%7B2%7D)
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The answer is tree even tho it was already answered
Increasing temperature does increase the amount of collision but it increases the kinetic energy of the molecules not the potential energy. Potential energy brings molecules together or apart (depending) and kinetic energy makes the molecules move around or not. Hope this helps