Plutonium−239 (t1/2 = 2.41 × 104 yr) represents a serious nuclear waste hazard. if seven half-lives are required to reach a tole
rable level of radioactivity, how long must 239 pu be stored? enter your answer in scientific notation.
2 answers:
Plutonium − 239 must be stored for = 1,687 .10 ^ 5 years to reach a tolerable level of radioactivity
<h3><em>Further explanation</em></h3>
The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually radioactive elements have an unstable atomic nucleus.
The main particles emitted by radioactive elements so that they generally decay are alpha (α), beta (β) and gamma (γ) particles
General formula used in decay:
Information :
T = duration of decay
t 1/2 = elemental half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
Plutonium − 239 has a half-life of t1/2 = 2.41 × 10⁴ years
To reach a tolerable level of radioactivity, Plutonium − 239 must be stored for 7 times half-life, namely:
= 7 x 2.41 × 10⁴ years
= 1,687 .10⁵ years
<h3><em>Learn more</em></h3>The identity of the missing nucleus
the process of radioactive decay
nuclear fusion and nuclear fission reactions
the product of radioactive decay
Keywords: decay, radioactive, Plutonium − 239, The atomic nucleus
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Answer : The 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.
Explanation :
Galvanic cell : It is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy. It is also known as the voltaic cell or electrochemical cell.
In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode.
We are taking the value of standard reduction potential form the standard table.
In this cell, the component that has lower standard reduction potential gets oxidized and that is added to the anode electrode. The second forms the cathode electrode.
The balanced two-half reactions will be,
Oxidation half reaction (Anode) :
Reduction half reaction (Cathode) :
Thus the overall reaction will be,
From this we conclude that, 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.
Hence, the 'Ag' is produced at the cathode electrode and 'Cu' is produced at anode electrode under standard conditions.
The molar mass of methylammonium bromide is 111u.
<h3>What is molar mass?</h3>The molar mass is defined as the mass per unit amount of substance of a given chemical entity.
Multiply the atomic weight (from the periodic table) of each element by the number of atoms of that element present in the compound.
Add it all together and put units of grams/mole after the number.
Atomic weight of H is 1u
Atomic weight of N is 14u
Atomic weight of C is 12u
Atomic weight of Br is 79u
Calculating molar mass of =2(1 x3+ 14+12+ 1 x 3 +79) = 111u
Hence, the molar mass of methylammonium bromide is 111u.
Learn more about molar mass here:
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