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Roman55 [17]
4 years ago
9

Candium forms the ion Sc3+. How many bromite ions could bond with Sc3+, and what would be the chemical formula?

Chemistry
1 answer:
wlad13 [49]4 years ago
7 0

Answer: 3 bromite ions and Sc(BrO_2)_3

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

Here scandium is having an oxidation state of +3 called as Sc^{3+} cation and bromite is an anion with oxidation state of -1 called as BrO_2^-. Thus 1 Scandium ion combines with three bromite ions and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Sc(BrO_2)_3

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Phosphorus has three unpaired electrons and hydrogen has one unpaired electron this means that_____ equivalents of hydrogen can
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Indicate whether the following balanced equations involve oxidation-reduction. Check all that apply. Check all that apply. 2H2SO
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Answer :  The balanced equations involve oxidation-reduction are:

(a) 2H_2SO_4(aq)+2NaBr(s)\rightarrow Br_2(l)+SO_2(g)+Na_2SO_4(aq)+2H_2O(l)

(b) 3SO_2(g)+2HNO_3(aq)+2H_2O(l)\rightarrow 3H_2SO_4(aq)+2NO(g)

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Explanation :

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Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

(a) The given chemical reaction is:

2H_2SO_4(aq)+2NaBr(s)\rightarrow Br_2(l)+SO_2(g)+Na_2SO_4(aq)+2H_2O(l)

This reaction involve oxidation-reduction reaction because the oxidation state bromine changes from (-1) to (0) which shows oxidation and sulfur changes from (+6) to (+4) which shows reduction.

(b) The given chemical reaction is:

3SO_2(g)+2HNO_3(aq)+2H_2O(l)\rightarrow 3H_2SO_4(aq)+2NO(g)

This reaction involve oxidation-reduction reaction because the oxidation state sulfur changes from (+4) to (+6) which shows oxidation and nitrogen changes from (+5) to (+2) which shows reduction.

(c) The given chemical reaction is:

NaI(aq)+3HOCl(aq)\rightarrow NaIO_3(aq)+3HCl(aq)

This reaction involve oxidation-reduction reaction because the oxidation state iodine changes from (-1) to (+5) which shows oxidation and chlorine changes from (+5) to (-1) which shows reduction.

(d) The given chemical reaction is:

PBr_3(l)+3H_2O(l)\rightarrow H_3PO_3(aq)+3HBr(aq)

This reaction does not involve oxidation-reduction reaction because the oxidation state of element present on reactant and product side are same.

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