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Roman55 [17]
3 years ago
9

Candium forms the ion Sc3+. How many bromite ions could bond with Sc3+, and what would be the chemical formula?

Chemistry
1 answer:
wlad13 [49]3 years ago
7 0

Answer: 3 bromite ions and Sc(BrO_2)_3

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

Here scandium is having an oxidation state of +3 called as Sc^{3+} cation and bromite is an anion with oxidation state of -1 called as BrO_2^-. Thus 1 Scandium ion combines with three bromite ions and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Sc(BrO_2)_3

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What is the correct formula for xenon hexafluoride? XeF XeF6 Xe6F6 Xe6F
Vinil7 [7]
Hexa- means six
"hexa-" and it is in front of the fluoride so that means we have 6 fluorines
Answer:
xenon hexafluoride → XeFl_{6}

Any questions?
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3 years ago
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Which of the following is not a form of energy?
Dafna1 [17]
The answer is pressure
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100.0 g of 4.0°C water is heated until its temperature is 37.0°C. If the specific heat of water is 4.184 J/g°C, calculate the am
Lady bird [3.3K]

Answer:

13.8072 kj

Explanation:

Given data:

Mass of water = 100.0 g

Initial temperature = 4.0 °C

Final temperature = 37.0°C

Specific heat capacity = 4.184 j/g.°C

Heat absorbed = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 37.0°C -  4.0 °C

ΔT = 33.0°C

Q = 100.0 g ×4.184 j/g.°C × 33.0°C

Q = 13807.2 j

Joule to KJ:

13807.2 j  × 1kj  /1000 j

13.8072 kj

5 0
3 years ago
What is the concentration of a solution with a volume of 660L that contains 33.4g of AlCO3?
lana [24]

Answer:

The concentration of the solution is 5.8168 × 10^{-4} mol.dm^{-3}

Explanation:

Here, we want to calculate the concentration of the solution.

The unit of this is mol/dm^3

So the first thing to do here is to calculate the number of moles of the solute present, which is the number of moles of AlCO3

The number of moles = mass/molar mass

molar mass of AlCO3 = 27 + 12 + 3(16)  = 27 + 12 + 48 = 87g/mol

Number of moles = 33.4/87 = 0.384 moles

This 0.384 moles is present in 660 L

x moles will be present in 1 dm^3

Recall 1 dm^3 = 1L

x * 660 = 0.384 * 1

x = 0.384/660 = 0.00058168 = 5.8168 * 10^-4 mol/dm^3

7 0
2 years ago
During an experiment, the percent yield of calcium chloride from a reaction was 85.22%. Theoretically, the expected amount shoul
devlian [24]

The formula to find yield is

(Actual Yield)/(Theorectical Yield) x100

Just do the math.

85.22% x 113 = 96.2986

Convert it to 3 significant figures

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7 0
3 years ago
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