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Roman55 [17]
4 years ago
9

Candium forms the ion Sc3+. How many bromite ions could bond with Sc3+, and what would be the chemical formula?

Chemistry
1 answer:
wlad13 [49]4 years ago
7 0

Answer: 3 bromite ions and Sc(BrO_2)_3

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.  

Here scandium is having an oxidation state of +3 called as Sc^{3+} cation and bromite is an anion with oxidation state of -1 called as BrO_2^-. Thus 1 Scandium ion combines with three bromite ions and their oxidation states are exchanged and written in simplest whole number ratios to give neutral Sc(BrO_2)_3

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timama [110]

Answer:

D

Explanation:

I hope this helps and have a great day

6 0
3 years ago
Consider the following balanced equation:
kow [346]

Answer:

The theoretical yield of Cu(s) in moles is 60.15 moles

Explanation:

Step 1: Data given

Number of moles CuO = 70.8 moles

Number of moles NH3 = 40.1 moles

Molar mass CuO = 79.545 g/mol

Molar mass NH3 = 17.03 g/mol

Step 2: The balanced equation

3CuO(s) + 2NH3(g) → 3H2O(l) + 3Cu(s) + N2(g)

For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2

NH3 is the limiting reactant. It will completely be consumed (40.1 moles). CuO is in excess. There will react 3/2 * 40.1 = 60.15 moles

There will remain 70.8 - 60.15 = 10.65 moles CuO

Step 3: Calculate moles Cu

For 3 moles CuO we need 2 moles NH3 to produce 3 moles H2O, 3 moles Cu and 1 mol N2

For 40.1 moles NH3 we'll have 60.15 moles Cu

The theoretical yield of Cu(s) in moles is 60.15 moles

8 0
4 years ago
How many moles would be equal to 22.4 g of CO2?
Rzqust [24]

Answer:

Number of moles = 0.51 mol

Explanation:

Given data:

Mass of CO₂ = 22.4 g

Number of moles = ?

Solution:

Number of moles of CO₂:

Number of moles = mass/molar mass

Molar mass of CO₂ = 44 g/mol

by putting values,

Number of moles = 22.4 g/ 44 g/mol

Number of moles = 0.51 mol

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