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babunello [35]
3 years ago
15

Phosphorus has three unpaired electrons and hydrogen has one unpaired electron this means that_____ equivalents of hydrogen can

react with ______ equivalents of phosphorus.
Chemistry
1 answer:
n200080 [17]3 years ago
7 0
<span>You can just swab the numbers and get the answer. The answer is: Phosphorus has three unpaired electrons and hydrogen has one unpaired electron this means that three equivalents of hydrogen can react with one equivalents of phosphorus.</span>
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Hi. Increased evaporation would be the greatest difference.

Explanation:

Have you ever had a drink in a mug with a lid? When you would remove the lid, all of the liquid on the lid is the liquid that would evaporate if there was no lid.

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What volume of carbon dioxide, at 1 atm pressure and 112°C, will be produced when 80.0 grams of methane is burned?
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Answer:

158 L.

Explanation:

What is given?

Pressure (P) = 1 atm.

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Molar mass of methane CH4 = 16 g/mol.

R constant = 0.0821 L*atm/mol*K.

What do we need? Volume (V).

Step-by-step solution:

To solve this problem, we have to use ideal gas law: the ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas. The formula is:

PV=nRT.

Where P is pressure, V is volume, n is the number of moles, R is the constant and T is temperature.

So, let's find the number of moles that are in 80.0 g of methane using its molar mass. This conversion is:

80.0g\text{ CH}_4\cdot\frac{1\text{ mol CH}_4}{16\text{ g CH}_4}=5\text{ moles CH}_4.

So, in this case, n=5.

Now, let's solve for 'V' and replace the given values in the ideal gas law equation:

V=\frac{nRT}{P}=\frac{5\text{ moles }\cdot0.0821\frac{L\cdot atm}{mol\cdot K}\cdot385K}{1\text{ atm}}=158.04\text{ L}\approx158\text{ L.}

The volume would be 158 L.

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1 year ago
If you initially have a volume of 4 L and a temperature of 300K. Then you decreased the volume to 2 L, what is the new temperatu
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Answer:

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Final temperature = ?

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According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

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Now we will put the values in formula.

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