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galben [10]
3 years ago
8

How many atoms of nitrogen on the reactant side

Chemistry
2 answers:
Taya2010 [7]3 years ago
6 0

Answer:

2 nitrogen atoms

Explanation:

nordsb [41]3 years ago
6 0
The answer is 2 nitrogen atoms
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Answer:

Electronegativity varies in a predictable way across the periodic table. Electronegativity increases from bottom to top in groups, and increases from left to right across periods. Thus, fluorine is the most electronegative element, while francium is one of the least electronegative.Explanation:

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Which of the statements listed below is negative aspect of a volcanic eruption?
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3 years ago
An analytical chemist weighs out 0.055g of an unknown triprotic acid into a 250mL volumetric flask and dilutes to the mark with
Katarina [22]

Answer:

Mass of the unknown acid is 4.0g

Explanation:

The determine the molar mass of the unknown acid, the steps below can be followed

Firstly, determine the concentration of the acid, the formula below can be used;

ConcA × Va/ConcB × Vb = Na/Nb

Where ConcA is the concentration of the unknown acid

ConcB is the concentration of the NaOH base

Va is the volume of acid and Vb is the volume of base

Since, the titration was said to have reached an equivalent point, it means the number of moles of the acid (Na) was equal to the number of moles of the base (Nb) and thus both will be assumed to be 1

Thus

ConcA × 250/0.13 × 6.6 = 1/1

ConcA = 0.13 × 6.6/250

ConcA = 0.003432M

Then, determine the actual number of moles (n) of the unknown acid used,

ConcA = no of moles of acid/volume of acid (in dm³ or L)

To convert mL to L, we divide by 1000

Hence, 250ml = 0.25L

0.003432 = n/0.25

n = 0.003432 × 0.25

n = 0.01373 moles

To determine the molar mass;

n = mass/molar mass

The mass was given in the question to be 0.055g

Thus

0.01373 = 0.055/molar mass

molar mass = 0.055/0.01373

molar mass = 4.0g

5 0
3 years ago
What group is helium in? Group 8 or group 2?
Gemiola [76]

Answer:

group 8 of the periodic table

Explanation:

7 0
3 years ago
Read 2 more answers
5. A compound with a formula of lead (Pb) and sulfur (S) was determined using the method in this experiment. A sample of Pb was
Airida [17]

Answer:

The mass of S that reacted is 0.642g

Explanation:

In this case we have

⇒ mass of crucible and cover, 25.429g

⇒ mass of crucible, cover, and Pb, 29.465g

⇒ mass of crucible, cover and commass of crucible and coverpound formed, 30.107g

The mass of Pb reacted = mass of crucible, cover, and Pb - mass of crucible and cover = 29.465 - 25.429 = 4.036g

The mass of compound formed = mass of crucible, cover and commass of crucible and coverpound formed  - mass of crucible and cover = 30.107 - 25.429g = 4.678g

The mass of S reacted = Mass of compound formed - mass of Pb reacted = 4.678 -4.036 = 0.642g

The mass of S that reacted is 0.642g

7 0
3 years ago
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