This is the transformations: See the picture, here we find the coordinate:
A' = (2,-3) and A''=(0.5,-2). There is many ways to get back to A from A'', i have showed one way (the red lines). This is done by going 5 units right and then 6 units up.
see image at https://imgur.com/a/fWQl8
Answer:
60cm^2
Step-by-step explanation:
We assume that is a circumscribing quadrilateral, rather than one that is circumscribed. It is also called a "tangential quadrilateral" and its area is ...
K = sr
where s is the semi-perimeter, the sum of opposite sides, and r is the radius of the incircle.
K = (12 cm) (5cm) = 60 cm²
_____
A quadrilateral can only be tangential if pairs of opposite sides add to the same length. Hence the given sum is the semiperimeter.
Answer:
The answer is D
Step-by-step explanation:
- Let's see all choices in detail
A . 0 it is correct because 0 is an integer
B .It seems like rational number but it is not simplified yet so -18 \ 2= -9
C .
![\sqrt{9} = 3 \: so \: it \: is \: also \: integer](https://tex.z-dn.net/?f=%20%5Csqrt%7B9%7D%20%20%3D%203%20%5C%3A%20so%20%5C%3A%20it%20%5C%3A%20is%20%5C%3A%20also%20%5C%3A%20integer)
D . 4\5 it is decimal so it is rational number not integer
I hope u like it
One thing everyone always forgets is we don't usually see the <em>entire</em> graph. Once out of the frame, these functions can do anything they want.
From what we can see, only the bottom right one is always decreasing.
Answer: bottom right
By the way, the top right graph (a vertical line) isn't a function.