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ch4aika [34]
3 years ago
5

Where did the element heavier than hydrogen and helium come from?

Physics
2 answers:
k0ka [10]3 years ago
7 0

Answer:

After the hydrogen in the star's core is exhausted, the star can fuse helium to form progressively heavier elements, carbon and oxygen and so on, until iron and nickel are formed. Elements heavier than that are formed in supernovas.

Explanation:

Snezhnost [94]3 years ago
6 0

They were produced inside stars.

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How did the South American plate and African plate move?
garri49 [273]

Answer:

How did the South American Plate and African Plate move? Earth's plates move on top of a soft, solid layer of rock called the mantle. ... The South American and African Plates moved apart as a divergent boundary formed between them and an ocean basin formed and spread.

Explanation:

pls make me brainliest

4 0
3 years ago
Read 2 more answers
When cars are equipped with flexible bumpers, they will bounce off each other during low-speed collisions, thus causing less dam
Len [333]

Answer:

Explanation:

Given that,

Mass of the heavier car m_1 = 1750 kg

Mass of the lighter car m_2 = 1350 kg

The speed of the lighter car just after collision can be represented as follows

m_1u_1+m_2u_2=m_1v_1+m_2v_2\\\\v_2=\frac{m_1u_1+m_2u_2-m_1v_1}{m_2}

v_2=\frac{(1850)(1.4)+(1450)(-1.10)-(1850)(0.250)}{1450} \\\\=\frac{2590+(-1595)-(462.5)}{1450} \\\\=\frac{2590-1595-462.5}{1450} \\\\=\frac{532.5}{1450}\\\\=0.367m/s

b) the change in the combined kinetic energy of the two-car system during this collision

\Delta K.E=(\frac{1}{2} m_1v_1^2+\frac{1}{2} m_2v_2^2)-(\frac{1}{2} m_1u_1^2+\frac{1}{2} m_2u_2^2)\\\\=\frac{1}{2} (m_1(v_1^2-u_1^2)+m_2(v_2^2-u_2^2))

substitute the value in the equation above

=\frac{1}{2} (1850((0.250)^2-(1.4)^2)+(1450((0.3670)^2-(-1.10)^2)\\\\=\frac{1}{2}(11850(0.0625-1.96)+(1450(0.1347)-(1.21))\\\\= \frac{1}{2}(11850(-1.8975))+(1450(-1.0753))\\\\=\frac{1}{2} (-3510.375+(-1559.185)\\\\=\frac{1}{2} (-5069.56)\\\\=-2534.78J

Hence, the change in combine kinetic energy is -2534.78J

8 0
3 years ago
Several light bulbs, each of resistance 1.5 Ω, are connected in a series across a 120 V source of emf. If the current through th
Leni [432]
<h3><u>Answer;</u></h3>

40 light bulbs

<h3><u>Explanation</u>;</h3>

The total resistance of components or bulbs in series is given as the sum of resistance of all the components.

Thus; if there are bulbs in series each with a resistance of 1.5 Ω, the the total resistance will be; 1.5nΩ

From the ohms law;

V = IR , where V is the voltage, I is the current and R is the resistor.

Thus; R = V/i

         R = 120/2

            = 60 Ω

But, there are n bulbs each with 1.5 Ω; thus there are;

n = 60/1.5

<u>  = 40 Bulbs </u>

7 0
3 years ago
4. A weightlifter lifts a set of weights a vertical distance of 2 meters. If a constant net force of 350 N is exerted on the wei
Ivanshal [37]

Answer:

700 J

Explanation:

Work = Force * Distance

Work = 350 N * 2 M = 700 J

3 0
2 years ago
Danielle is applying 25.2 N to the right on her sled. The sled has a mass of 15.7 kg, and
Sever21 [200]

The applied force is parallel to the ground, so the net vertical force on the sled is 0. By Newton's second law, this means the normal force and weight of the sled cancel out:

<em>n</em> - <em>w</em> = 0

<em>n</em> = <em>w</em>

<em>n</em> = <em>m g</em>

<em>n</em> = (15.7 kg) (9.80 m/s²)

<em>n</em> = 153.86 N

4 0
3 years ago
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