Answer:
The law of conservation of momentum states that the total momentum of interacting objects does not <u>change</u>. This means the total momentum <u>before</u><u> </u>a collision or explosion is equal to the total momentum <u>after</u><u> </u>a collision or explosion.
Answer:
the answer is calcium....
Answer:
The correct answer is ![2.8*10^{-5}ms^{-1}](https://tex.z-dn.net/?f=2.8%2A10%5E%7B-5%7Dms%5E%7B-1%7D)
Explanation:
The formula for the electron drift speed is given as follows,
![u=I/nAq](https://tex.z-dn.net/?f=u%3DI%2FnAq)
where n is the number of of electrons per unit m³, q is the charge on an electron and A is the cross-sectional area of the copper wire and I is the current. We see that we already have A , q and I. The only thing left to calculate is the electron density n that is the number of electrons per unit volume.
Using the information provided in the question we can see that the number of moles of copper atoms in a cm³ of volume of the conductor is
. Converting this number to m³ using very elementary unit conversion we get
. If we multiply this number by the Avagardo number which is the number of atoms per mol of any gas , we get the number of atoms per m³ which in this case is equal to the number of electron per m³ because one electron per atom of copper contribute to the current. So we get,
![n=140384*6.02*10^{23} = 8.45*10^{28}electrons.m^{-3}](https://tex.z-dn.net/?f=n%3D140384%2A6.02%2A10%5E%7B23%7D%20%3D%208.45%2A10%5E%7B28%7Delectrons.m%5E%7B-3%7D)
if we convert the area from mm³ to m³ we get
.So now that we have n, we plug in all the values of A ,I ,q and n into the main equation to obtain,
![u=30/(8.45*10^{28}*80*10^{-6}*1.602*10^{-19})\\u=2.8*10^{-5}m.s^{-1}](https://tex.z-dn.net/?f=u%3D30%2F%288.45%2A10%5E%7B28%7D%2A80%2A10%5E%7B-6%7D%2A1.602%2A10%5E%7B-19%7D%29%5C%5Cu%3D2.8%2A10%5E%7B-5%7Dm.s%5E%7B-1%7D)
which is our final answer.