3 years ago

Where did the element heavier than hydrogen and helium come from?

2 answers:

7 0

Answer:

After the hydrogen in the star's core is exhausted, the star can fuse helium to form progressively heavier elements, carbon and oxygen and so on, until iron and nickel are formed. Elements heavier than that are formed in supernovas.

Explanation:

Snezhnost [94]3 years ago

6 0

They were produced inside stars.

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Make the following conversion

ValentinkaMS [17]

Answer:

The value of 60.2 mg in to g is 0.0602.

Explanation:

We need to calculate the 60.2 mg in to gram.

Conversion mg to g :

1 g = 1000 mg

Using this conversion,

$1 mg = 10^{-3}g$

So, $60.2\ mg = 60.2\times10^{-3}\ g$

$60.2\times10^{-3}\ g$

Hence, The value of 60.2 mg in to g is 0.0602.

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3 years ago

Which two statements explain reasons to use a computer program to encode

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Answer:a

Explanation:why not

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3 years ago

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A 1100 kg car pushes a 1800 kg truck that has a dead battery. When the driver steps on the accelerator, the drive wheels of the

12345 [234]

Answer:The answer is 3000 N.

Force (F) is the multiplication of mass (m) and acceleration (a).

F = m · a

It is given:

mc = 1000 kg

mt = 2000 kg

total force: F = 4500 N

total mass: m = mc + mt

Let's calculate acceleration which is common:

a = F/m = F/(mc + mt) = 4500/(1000 + 2000) = 4500/3000 = 1.5 m/s²

Now, when we know acceleration, let's calculate force on the truck:

Ft = mt · a = 2000 · 1.5 = 3000 N

Explanation:

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3 years ago

How do you increase the potential energy of an apple

m_a_m_a [10]

To increase the potential energy of any object, not limited to an apple, you have to hold it higher.

5 0

3 years ago

If the voltage across a circuit of constant resistance is doubled, the power dissipated by that circuit will

densk [106]

Answer:

The voltage will quadruple

Explanation:

The power dissipated in a circuit is given by

$P=\frac{V^2}{R}$

where

V is the voltage

R is the resistance

In this problem, the voltage across the circuit is doubled:

V' = 2V

So the new power dissipated is

$P'=\frac{V'^2}{R}=\frac{(2V)^2}{R}=4\frac{V^2}{R}=4 P$

so, the power dissipated will quadruple.

6 0

3 years ago