Answer:
B. The mass of Mars is less than the mass of Earth.
Explanation:
Mass of an object is the constant anywhere in the universe.
The weight of an object is equal to the gravitational force acting on it.
Weight is given by
where
G = Gravitational constant
M = Mass of Planet
R = Radius of planet
m = Mass of object
g = Acceleration due to gravity
So weight of an object depends on the acceleration due to gravity on that planet. The acceleration due to gravity depends on the mass and radius of the planet.
The weight of the object is less on Mars because mars has less mass compared to Earth.
Let l = Q/L = linear charge density. The semi-circle has a length L which is half the circumference of the circle. So w can relate the radius of the circle to L by
<span>C = 2L = 2*pi*R ---> R = L/pi </span>
<span>Now define the center of the semi-circle as the origin of coordinates and define a as the angle between R and the x-axis. </span>
<span>we can define a small charge dq as </span>
<span>dq = l*ds = l*R*da </span>
<span>So the electric field can be written as: </span>
<span>dE =kdq*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>
<span>dE = k*I*R*da*(cos(a)/R^2 I_hat + sin(a)/R^2 j_hat) </span>
<span>E = k*I*(sin(a)/R I_hat - cos(a)/R^2 j_hat) </span>
<span>E = pi*k*Q/L(sin(a)/L I_hat - cos(a)/L j_hat)</span>
Answer:
Because the output force is greater than the input force, the input distance must be greater than the output distance.
Explanation:
