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LuckyWell [14K]
3 years ago
6

a turtle swimming in a straight line toward shore has a speed of 0.50 m/s after 4.0s its speed is 0.80 m/s what is the turtle's

average acceleration ​
Physics
1 answer:
bagirrra123 [75]3 years ago
5 0

Answer:

sdfv

Explanation:

s.dkvn

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SOH-CAH-TOA is used to solve for the ________
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Answer:

c. initial (x and y)

Explanation:

When a projectile is launched at a velocity with a launch angle, to solve it, we must first resolve the initial velocity into the x and y components. To do this will mean we have to treat it like a triangle due to the launch angle and the direction of the projectile.

Therefore, we will have to make use of trigonometric ratios which is also known by the mnemonic "SOH CAH TOA"

Thus, this method resolves the initial x and y velocities.

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Is 5g greater than 20.43 mg
worty [1.4K]

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What is the pendulum length whose period is 2.0s ?
Mashutka [201]
Formula\ for\ period:\\\ T=2 \pi \sqrt{\frac{L}{g}}\\\ g-gravity=9,8 \frac{m}{s^2} ,\ L-pendulum \ length \\\\ \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\\\ \frac{T^2}{2 \pi } = \frac{L}{g} \\\\\ \frac{T^2}{2 \pi }*g=L\\\\ L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24mT=2 \pi   \sqrt{\frac{L}{g}} \\
 \frac{T}{2 \pi } = \sqrt{ \frac{L}{g} }|square\\
 \frac{T^2}{2 \pi }  = \frac{L}{g} \\
 \frac{T^2}{2 \pi }*g=L\\
L= \frac{2^2}{2*3,14 }*9,8= \frac{39,2}{6,28} =6,24m

7 0
3 years ago
30 POINTS! (Question is located in picture under graph)
harkovskaia [24]
Hi i think its E because the the numbers on both sides are to spread out and are not even one side is 4 and the other is 3
8 0
4 years ago
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Can I get help and an explanation on C?
Diano4ka-milaya [45]

Answer:

1.67 m/s

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Momentum is conserved.

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(30 kg) (10 m/s) + (35 kg) (-10 m/s) = (30 kg) v + (35 kg) (0 m/s)

300 - 350 = 30v

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Linus will move at 1.67 m/s in the direction opposite that he started.

6 0
3 years ago
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