Co carbon monoxide
sorry friend i don't know other ones
Answer:
Current = 8696 A
Fraction of power lost =
= 0.151
Explanation:
Electric power is given by

where I is the current and V is the voltage.

Using values from the question,

The power loss is given by

where R is the resistance of the wire. From the question, the wire has a resistance of
per km. Since resistance is proportional to length, the resistance of the wire is

Hence,

The fraction lost = 
Hope this shows! It has all the equations for all of the problems u asked in the comments
Answer:
The amount of heat or moisture in the air
Explanation:
Or a switch