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Why is the use of wood as a fuel not advisable the forests can be replenished
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The correct answer is "As the distance from the earth increases, the gravitational pull on the spaceship would decrease."
In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by
where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.
In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by
where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.
The reason why there is a difference between free-fall acceleration is a centrifugal force.
I attached a diagram that shows how this force aligns with the force of gravity.
From the diagram we can see that:
Where g' is the free-fall acceleration when there is no centrifugal force, r is the radius of the planet, and w is angular frequency of planet's rotation.
is the latitude.
We can calculate g' and wr^2 from the given conditions in the problem.
Our final equation is:
Colatitude is:
The answer is:
I attached a diagram that shows how this force aligns with the force of gravity.
From the diagram we can see that:
Where g' is the free-fall acceleration when there is no centrifugal force, r is the radius of the planet, and w is angular frequency of planet's rotation.
We can calculate g' and wr^2 from the given conditions in the problem.
Our final equation is:
Colatitude is:
The answer is: