1) y=(7/2)x-2.
Slope is the coefficient of x, that is 7/2
Intercept x is the value of x when y = 0 ==> 0=(7/2) X - 2==> 7/2x=2 &x=4/7
so intercept x, (4/7,0)
Intercept y is the value of y when x=0 ==> y= (7/2).(0) - 2 ==> y = 2
and so intercept y, (0,-2)
Now you will follow the same logic to find the are same questions
2) y= -6x + 3 ==>Slope= -6, Intercept x =1/2 & intercept y=3
3) y=-5 has a slope 0 (it doesn't exist). The graph is a line // to x-axis at y=-5
4)y=(6/5)x + 1:==>Slope= -5/6, Intercept x =-5/6 & intercept y=1
5) y=(1/4)x + 2 ==>Slope= 1/4, Intercept x =-8 & intercept y=2
6) x=5, this ligne is // to y axis at x=-5
what is b? from the first equation in the system, y + 2 = b.
About 5 hours. I did this by dividing and rounding 276 by 62. Hope this helps!
Answer:
<h2>y - 5 = -1(x + 3)</h2>
Step-by-step explanation:
The point-slope form of an equation of a line:
m - slope
We have m = -1 and the point (-3, 5). Substitute:
Step-by-step explanation:
sqrt(5x)×(sqrt(8x²) - 2×sqrt(x)) =
sqrt(5x × 8x²) - 2×sqrt(5x × x) =
sqrt(40x) × x - 2x × sqrt(5) =
2x×sqrt(10x) - 2x×sqrt(5)
therefore, the last option is correct.
