Answer:
(a): 2ZnO(s) -----------> 2Zn(s) + O2(g)
2C(s) + O2(g) ---------> 2CO(g)
(b): ZnO(s) + C(s) ---------> Zn(s) + CO(g)
Answer:
0.00353J/g/°C
Explanation:
I will assume the temperature of the ice to be approximately 0°C.
Moreover, Heat of fusion of water is 6kJ
Amount of heat used to melt 5.3g of ice = 5.3 x 6 / 18
=1.767g°C
Therefore
1.767 = 25 x specific heat cap. x 200
Specific heat cap. = 1.767/(25x200)
= 0.00353J/g/°C
Answer:
2Li(s) + ⅛S₈(s, rhombic) + 2O₂(g) → Li₂SO₄(s)
Explanation:
A thermochemical equation must show the formation of 1 mol of a substance from its elements in their most stable state,.
The only equation that meets those conditions is the last one.
A and B are wrong , because they show Li₂SO₄ as a reactant, not a product.
C is wrong because Li⁺ and SO₄²⁻ are not elements.
D is wrong because it shows the formation of 8 mol of Li₂SO₄.
Answer : The given compound belongs to ether and alcohol.
Explanation :
The chemical formula of the given compound is, 
First we have to calculate the degree of unsaturation.
Formula used:
Degree of unsaturation = 
where,
C = number of carbon
H = number of hydrogen
N = number of nitrogen
X = number of halogen
Degree of unsaturation = 
The degree of unsaturation is, 0 that means there is no double or triple bond in the compound only single bond is present between the atoms.
Thus, the given compound belongs to ether and alcohol.
