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Anon25 [30]
3 years ago
10

For the reaction shown, calculate how many moles of NH3 form when 16.72 moles of reactant completely reacts:

Chemistry
1 answer:
Agata [3.3K]3 years ago
8 0

Answer : The moles of NH_3 formed are, 22.3 moles.

Explanation : Given,

Moles of N_2H_4 = 16.72 mol

The given chemical reaction is:

3N_2H_4(l)\rightarrow 4NH_3(g)+2N_2(g)

From the balanced chemical reaction, we conclude that:

As, 3 moles of N_2H_4 react to give 4 moles of NH_3

So, 16.72 moles of N_2H_4 react to give \frac{4}{3}\times 16.72=22.3 moles of NH_3

Therefore, the moles of NH_3 formed are, 22.3 moles.

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15.1 L N2 at 25 °C and 125 kPa and 44.3 L O2 at 25 °C and 125 kPa were transferred to a tank with a volume of 6.25 L. What is th
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Answer:

The total pressure of the mixture in the tank of volume 6.25 litres at 51°C  is 1291.85 kPa.

Explanation:

For N2,

                Pressure(P₁)=125 kPa

                  Volume(V₁)=15·1 L

                Temperature (T₁)=25°C=25+273 K=298 K

Similarly, for Oxygen,

                   Pressure(P₂)= 125 kPa

                   Volume(V₂)= 44.3 L

                  Temperature(T₂)=25°C= 298 K

Then, for the mixture,

              Volumeof the mixture( V)= 6.25 L

                                     Pressure(P)=?

                Temperature (T)= 51°C = 51+273 K=324 K

Then, By Combined gas laws,

                                 \frac{P_{1} V_{1} }{T_{1} } +\frac{P_{2} V_{2} }{T_{2} } =\frac{PV}{T}

                      or, \frac{15.1*125}{298} +\frac{44.3*125}{298} =\frac{P*6.25}{324}

                     or, 6.34+18.58=\frac{P*6.25}{324}

                     or, P=\frac{24.92*324}{6.25}

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3 years ago
What is the noble-gas configuration for As​
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Answer:

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Arsenic is metalloid.

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Its atomic mass is 75 amu.

Its symbol is As.

It is usually present in combine with sulfur and metals.

it is used in bronzing.

It is also used for hardening.

Electronic configuration:

As₃₃ = Is² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p³

Noble gas Electronic configuration:

As₃₃ = [Ar] 3d¹⁰ 4s² 4p³

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