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2 years ago

A bullet (m=20g) shot with a speed of 800 m/s hits an oak tree and sticks 4cm inside it.

Physics

1 answer:

Tcecarenko [31]2 years ago

6 0

Hi there!

We can begin by converting cm to m:

4cm = 0.04 m

Use the following equation:

vf² = vi² + 2ad

The final velocity is 0 m/s, so:

0 = vi² + 2ad

vi² = -2(a)d

Plug in given values to solve for the acceleration:

800²/2(0.04) = -a

a = -8,000,000 m/s²

Find the force using the equation:

F = ma

F = (0.02)(-8,000,000) = -160,000 N

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A 150 kg boy and his bike are traveling 12 m/s when he slams on his breaks and stop at his friend’s house. How much impulse is r

Nataly [62]

Answer:

J = 1800 kg-m/s

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Mass of a boy, m = 150 kg

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Finally, it stops, v = 0

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3 years ago

A 35 kg box rests on the back of a truck. The coefficient of static friction bet?005 (part 1 of 2)A 35 kg box rests on the back

elena-14-01-66 [18.8K]

Answer with Explanation:

We are given that

Mass of box=35 kg

Coefficient of static friction between box and truck bed=0.202

Acceleration due to gravity= $9.8 m/s^2$

a.We have to find the force by which the box accelerates forward.

Force by which box accelerates= $\mu mg=0.202\times 9.8\times 35$

Force by which box accelerates= $62.286 N$

b.We have to find the maximum acceleration can the truck have before the box slides.

Force =friction force

$ma=\mu mg$

$a=\mu g=9.8\times 0.202=1.9796 m/s^2$

Hence, the truck can have maximum acceleration before the box slide= $1.9796 m/s^2$

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3 years ago