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Dennis_Churaev [7]
3 years ago
12

What does a banana have that a human does not?

Chemistry
2 answers:
NARA [144]3 years ago
8 0

Answer:

appealing taste

ba dump shhhh

um i dont know if this was a real question

Explanation:

Vikentia [17]3 years ago
7 0
It would be a face or toes
You might be interested in
A sample of 17.0 M concentrated H2SO4 stock solution with a volume of 25.0 cm3 was diluted to final concentration of 5.0 M H2SO4
Art [367]

Answer:

60 cm³ of water

Explanation:

We'll begin by calculating the volume of the diluted solution. This can be obtained as follow:

Concentration of stock solution (C₁) = 17 M

Volume of stock solution (V₁) = 25 cm³

Concentration of diluted solution (C₂) = 5 M

Volume of diluted solution (V₂) =?

C₁V₁ = C₂V₂

17 × 25 = 5 × V₂

425 = 5 × V₂

Divide both side by 5

V₂ = 425 / 5

V₂ = 85 cm³

Thus, the volume of the diluted solution is 85 cm³

Finally, we shall determine the volume of water needed to dilute the solution. This can be obtained as follow:

Volume of stock solution (V₁) = 25 cm³

Volume of diluted solution (V₂) = 85 cm³

Volume of water =?

Volume of water = V₂ – V₁

Volume of water = 85 – 25

Volume of water = 60 cm³

Therefore, 60 cm³ of water is needed to dilute the solution.

6 0
2 years ago
) determine the theoretical yield and the percent yield if 21.8 g of k2co3 is produced from reacting 27.9 g ko2 with 29.0 l of c
Airida [17]
The Balanced Chemical Equation is as follow;

                         4 KO₂  +  2 CO₂    →    2 K₂CO₃  +  3 O₂

First find out the Limiting Reagent,
According to equation,

         284 g (4 moles) KO₂ reacted with  =  44.8 L (2 moles) of CO₂
So,
                  27.9 g of KO₂ will react with  =  X  L of CO₂


Solving for X,
                          X  =  (44.8 L × 27.9 g) ÷ 284 g

                          X  =  4.40 L of CO₂

Hence, to consume 27.9 g of KO₂ only 4.40 L CO₂ is required, while, we are provided with 29 L of CO₂, it means CO₂ is in excess and KO₂ is is limited amount, Therefore, KO₂ will control the yield of K₂CO₃. So,

According to eq.

         284 g (4 moles) KO₂ formed  =  138.2 g of K₂CO₃
So,
         27.9 g of KO₂ will form  =  X g of K₂CO₃

Solving for X,
                        X  =  (138.2 g × 27.9 g) ÷ 284 g

                        X  =  13.57 g of K₂CO₃

So, 13.57 g of K₂CO₃ formed is the theoretical yield.

%age Yield  =  13.57 / 21.8 × 100

%age Yield  =  62.24 %
3 0
3 years ago
Read 2 more answers
When a solution of cesium chloride (CsCl) is subjected to high-speed centrifugation, a stable density gradient is formed.
Natali5045456 [20]
A as in false YWWEEEW
7 0
3 years ago
What are the 6 types of chemical reactions?
marusya05 [52]

Answer:

Combination.

Decomposition.

Single displacement.

Double displacement.

Combustion.

Redox.

6 0
3 years ago
Read 2 more answers
How many chlorine atoms are found in 8.3 moles of chlorine?
erik [133]

Answer:

5*10²⁴ chlorine atoms are found in 8.3 moles of chlorine.

Explanation:

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number represents a quantity without an associated physical dimension, so it is considered a pure number that allows describing a physical characteristic without an explicit dimension or unit of expression. Avogadro's number applies to any substance.

Then you can apply the following rule of three: if 1 mole of the compound contains 6.023 * 10²³ atoms, 8.3 moles of the compound how many atoms does it have?

amount of atoms=\frac{8.3 moles*6.023*10^{23}atoms }{1 mole}

amount of atoms≅ 5*10²⁴ atoms

<u><em>5*10²⁴ chlorine atoms are found in 8.3 moles of chlorine.</em></u>

4 0
3 years ago
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