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TEA [102]
3 years ago
11

Energy from the Sun arrives at the top of the Earth's atmosphere with an intensity of 1.1 kW/m2 . How long does it take for 1.91

×109 J to arrive on an area of 1 m2 ?
Chemistry
1 answer:
Stels [109]3 years ago
3 0

Answer:

1.736 × 10⁶

Explanation:

Data provided in the question:

Intensity of the energy received from the sun = 1.1 kW/m² = 1.1 × 10³ W/m²

Energy  required to arrive = 1.91 × 10⁹ J

Area at the surface = 1 m²

Now,

we know that

Energy = Intensity × Area × Time

or

1.91 × 10⁹ = ( 1.1 × 10³ ) × 1 × Time

or

Time = [ 1.91 × 10⁹ ] ÷ [ 1.1 × 10³ ]

or

Time = 1.736 × 10⁶

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PV = nRT\\0.95 atm \times 7.62 L = n \times 0.0821 L atm/mol K \times 360.5 K\\n = \frac{0.95 atm \times 7.62 L}{0.0821 L atm/mol K \times 360.5 K}\\= \frac{7.239}{29.59705}\\= 0.244 mol

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