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Gekata [30.6K]
3 years ago
11

What can I do to stay positive from bad things like commits?

Physics
1 answer:
____ [38]3 years ago
4 0

Answer:

u can listen to good music that makes u happy

ignore them and dont talk to them. engage it makes things worse

u can smile, and follow ur passion and do something u love

always put out kindness even when people are being meen

Explanation:

have a great day and remember to never give up on hope it will come one way or another, sooner or later :) :) :) :) :) :)

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To practice Tactics Box 9.1 Calculating the Work Done by a Constant Force. Recall that the work W done by a constant force F⃗ at
insens350 [35]

Answer:

The vector magnitudes F and r are always postive, so the sign o W is determined entirely by the angle e between the force and the displacement.Submit Figure 1 off 1 part C

3 0
3 years ago
Read 2 more answers
A 10.0 V battery is connected across two resistors in series. One resistor has resistance of 840.0 Ω and the other has resistanc
REY [17]

Answer:

Explanation:

There are a couple of ways you could do this.

The easiest is to use E*R1/(R1 + R2)

  • E = 10 volts
  • R1 = 590 ohms
  • R2 = 840 ohms

So the result would be

E_590 = 10 * 590/(590 + 840)

E_590 = 10 * 590/ (1430)

E_590 = 4.13 volts rounded.

You could do this a slightly longer way.

R = 1430 (total ohms in series.

E = 10 volts

I = ???

I = E/R

I = 10 / 1430

I = 0.00699

Now use this current to figure out the voltage drop.

E = I * R

I = 0.00699 amps

R = 590 ohms

E = 0.00699 * 590

E = 4.13 volts

Pick the way of doing it you like best.

4 0
4 years ago
Which term describes the light-sensitive structures found on the retina?
miss Akunina [59]
The answer would be 
C. Rods and Cones 
6 0
3 years ago
Read 2 more answers
A horizontal beam of electrons initially moving at 4.0×10^7 m/s is deflected vertically by the vertical electric field between o
givi [52]

Answer:

1.77\times 10^{-7}\ C/m^2

0.000439077936334 m

Explanation:

q = Charge of electron = 1.6\times 10^{-19}\ C

E = Electric field = 2\times 10^{4}\ N/C

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

d = Distance between plates = 2 cm (assumed)

m = Mass of electron = 9.11\times 10^{-31}\ kg

The beam consists of electrons which means it has negative charge this means the upper plates will be positive and the lower plate will be negative.

The direction is upper to lower lower plate.

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

Electric flux is given by

\phi=\epsilon_0E\\\Rightarrow \phi=8.85\times 10^{-12}\times 2\times 10^{4}\\\Rightarrow \phi=1.77\times 10^{-7}\ C/m^2

The charge per unit area on the plates is 1.77\times 10^{-7}\ C/m^2

Deflection is given by

s=\dfrac{1}{2}\dfrac{qE}{m}(\dfrac{d}{v})^2\\\Rightarrow s=\dfrac{1}{2}\dfrac{1.6\times 10^{-19}\times 2\times 10^4}{9.11\times 10^{-31}}(\dfrac{0.02}{4\times 10^7})^2\\\Rightarrow s=0.000439077936334\ m

The deflection is 0.000439077936334 m

7 0
3 years ago
An elevator motor in a high-rise building can do 3500 kJ of work in 5 min. Find the power developed by the motor. Explain if you
Ilya [14]

Answer:

P = 11666.6 W

Explanation:

Given that,

Work done by the motor, W = 3500 kJ

Time, t = 5 min = 300 s

We need to find the power developed by the motor. Power developed is given by :

P=\dfrac{E}{t}\\\\P=\dfrac{3500\times 10^3}{300}\\\\P=11666.7\ W

So, the required power is 11666.6 W.

4 0
3 years ago
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