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zalisa [80]
4 years ago
6

Assuming that the smallest measurable wavelength in an experiment is 0.610 fm (femtometers), what is the maximum mass of an obje

ct traveling at 199 m·s–1 for which the de Broglie wavelength is observable?.

Physics
2 answers:
frosja888 [35]4 years ago
7 0
<span>1 fm = 1.0 × 10-15 meters 
</span>so
0.610<span>  fm x (1.0x10^-15 m / 1 fm)
                   = 6.1x10^-16 m</span>
so the formula is
λ = h / mu 
so,
as we know mass value so by putting
<span>m = (6.626*10^-34)/(6.1*10^-16*199)
    =</span>(6.626*10^-34)/(1213.96*<span>10^-16)
</span>    = 5.45 x 10^ -21

KonstantinChe [14]4 years ago
7 0

The maximum mass of the object is about 5.46 × 10⁻²¹ kg

\texttt{ }

<h3>Further explanation</h3>

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:

\large {\boxed {E = h \times f}}

<em>E = Energi of A Photon ( Joule )</em>

<em>h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )</em>

<em>f = Frequency of Eletromagnetic Wave ( Hz )</em>

\texttt{ }

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}

\large {\boxed {E = qV + \Phi}}

<em>E = Energi of A Photon ( Joule )</em>

<em>m = Mass of an Electron ( kg )</em>

<em>v = Electron Release Speed ( m/s )</em>

<em>Ф = Work Function of Metal ( Joule )</em>

<em>q = Charge of an Electron ( Coulomb )</em>

<em>V = Stopping Potential ( Volt )</em>

Let us now tackle the problem!

\texttt{ }

This problem is about De Broglie's wavelength.

<u>Given:</u>

speed of object = v = 199 m/s

wavelength = λ  = 0.610 fm = 6.1 × 10⁻¹⁶ m

Planck's constant = h = 6.63 × 10⁻³⁴ Js

<u>Asked:</u>

mass of the object = m = ?

<u>Solution:</u>

\lambda = \frac{h}{mv}

6.1 \times 10^{-16} = \frac{6.63 \times 10^{-34}}{m \times 199}

\large {\boxed {m \approx 5.46 \times 10^{-21} \texttt{ kg}} }

\texttt{ }

<h3>Learn more</h3>
  • Photoelectric Effect : brainly.com/question/1408276
  • Statements about the Photoelectric Effect : brainly.com/question/9260704
  • Rutherford model and Photoelecric Effect : brainly.com/question/1458544
  • Photoelectric Threshold Wavelength : brainly.com/question/10015690

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Quantum Physics

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Answer:

Ro = 7.8 [g/cm³]

Explanation:

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V_{n}=110[cm^{3} ]\\V_{o}=100[cm^{3} ]\\V_{d}=110-100 = 10 [cm^{3} ]

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Ro = 78/10\\Ro = 7.8 [g/cm^{3} ]

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3 years ago
A rock thrown with speed 12.0 m/s and launch angle 30.0 ∘ (above the horizontal) travels a horizontal distance of d = 15.5 m bef
Dimas [21]

Supposing there's no air resistance, horizontal velocity is constant, which makes it very easy to solve for the amount of time that the rock was in the air.


Initial horizontal velocity is: <span>
cos(30 degrees) * 12m/s = 10.3923m/s 

15.5m / 10.3923m/s = 1.49s 

So the rock was in the air for 1.49 seconds. </span>

<span>

Now that we know that, we can use the following kinematics equation: 

d = v i * t + 1/2 * a * t^2 

Where d is the difference in y position, t is the time that the rock was in the air, and a is the vertical acceleration: -9.80m/s^2. </span>

<span>
Initial vertical velocity is sin(30 degrees) * 12m/s = 6 m/s 

So: 

d = 6 * 1.49 + (1/2) * (-9.80) * (1.49)^2 
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d = -1.95<span>

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5 0
3 years ago
Help me with this please!!!!!!!!!!!!!!!!
olga55 [171]

Answer:

what do you need help with?

Explanation:

I would look up the periodic table of elements

hope this helps!

6 0
3 years ago
The speed of a tennis ball that is served is 73.14 m/s. During a serve, the ball typically starts from rest and is in contact wi
Serga [27]

Answer: Third option

F = 250w

Explanation:

The impulse can be written as the product of force for the time interval in which it is applied.

I = F (t_2-t_1)

You can also write impulse I as the change of the linear momentum of the ball

I = mv_2 -mv_1

So:

F (t_2-t_1) = mv_2 -mv_1

We want to find the force applied to the ball. We know that

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The initial velocity v_1 is zero.

The final speed v_2 = 73.14\ m / s

So

F * 0.03 = 73.14m

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We must express the result of the force in terms of the weight of the ball.

We divide the expression between the acceleration of gravity

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The answer is the third option

3 0
3 years ago
Easy quiz easy points 7
Darya [45]
The answer is 2: hush
5 0
3 years ago
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