Assuming that the smallest measurable wavelength in an experiment is 0.610 fm (femtometers), what is the maximum mass of an obje

Question

zalisa [80]

4 years ago

6

Assuming that the smallest measurable wavelength in an experiment is 0.610 fm (femtometers), what is the maximum mass of an obje

ct traveling at 199 m·s–1 for which the de Broglie wavelength is observable?.

Physics

2 answers:

frosja888 [35] · Answer 1 · 2021-11-25T12:56:32+03:00

1 fm = 1.0 × 10-15 meters
so
0.610 fm x (1.0x10^-15 m / 1 fm)
= 6.1x10^-16 m
so the formula is
λ = h / mu
so,
as we know mass value so by putting
m = (6.626*10^-34)/(6.1*10^-16*199)
=(6.626*10^-34)/(1213.96*10^-16)
 = 5.45 x 10^ -21

KonstantinChe [14] · Answer 2 · 2021-11-25T14:06:46+03:00

The maximum mass of the object is about 5.46 × 10⁻²¹ kg

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<h3>Further explanation</h3>

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:

$\large {\boxed {E = h \times f}}$

E = Energi of A Photon ( Joule )

h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )

f = Frequency of Eletromagnetic Wave ( Hz )

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The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

$\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}$