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zalisa [80]
4 years ago
6

Assuming that the smallest measurable wavelength in an experiment is 0.610 fm (femtometers), what is the maximum mass of an obje

ct traveling at 199 m·s–1 for which the de Broglie wavelength is observable?.

Physics
2 answers:
frosja888 [35]4 years ago
7 0
<span>1 fm = 1.0 × 10-15 meters 
</span>so
0.610<span>  fm x (1.0x10^-15 m / 1 fm)
                   = 6.1x10^-16 m</span>
so the formula is
λ = h / mu 
so,
as we know mass value so by putting
<span>m = (6.626*10^-34)/(6.1*10^-16*199)
    =</span>(6.626*10^-34)/(1213.96*<span>10^-16)
</span>    = 5.45 x 10^ -21

KonstantinChe [14]4 years ago
7 0

The maximum mass of the object is about 5.46 × 10⁻²¹ kg

\texttt{ }

<h3>Further explanation</h3>

The term of package of electromagnetic wave radiation energy was first introduced by Max Planck. He termed it with photons with the magnitude is:

\large {\boxed {E = h \times f}}

<em>E = Energi of A Photon ( Joule )</em>

<em>h = Planck's Constant ( 6.63 × 10⁻³⁴ Js )</em>

<em>f = Frequency of Eletromagnetic Wave ( Hz )</em>

\texttt{ }

The photoelectric effect is an effect in which electrons are released from the metal surface when illuminated by electromagnetic waves with large enough of radiation energy.

\large {\boxed {E = \frac{1}{2}mv^2 + \Phi}}

\large {\boxed {E = qV + \Phi}}

<em>E = Energi of A Photon ( Joule )</em>

<em>m = Mass of an Electron ( kg )</em>

<em>v = Electron Release Speed ( m/s )</em>

<em>Ф = Work Function of Metal ( Joule )</em>

<em>q = Charge of an Electron ( Coulomb )</em>

<em>V = Stopping Potential ( Volt )</em>

Let us now tackle the problem!

\texttt{ }

This problem is about De Broglie's wavelength.

<u>Given:</u>

speed of object = v = 199 m/s

wavelength = λ  = 0.610 fm = 6.1 × 10⁻¹⁶ m

Planck's constant = h = 6.63 × 10⁻³⁴ Js

<u>Asked:</u>

mass of the object = m = ?

<u>Solution:</u>

\lambda = \frac{h}{mv}

6.1 \times 10^{-16} = \frac{6.63 \times 10^{-34}}{m \times 199}

\large {\boxed {m \approx 5.46 \times 10^{-21} \texttt{ kg}} }

\texttt{ }

<h3>Learn more</h3>
  • Photoelectric Effect : brainly.com/question/1408276
  • Statements about the Photoelectric Effect : brainly.com/question/9260704
  • Rutherford model and Photoelecric Effect : brainly.com/question/1458544
  • Photoelectric Threshold Wavelength : brainly.com/question/10015690

\texttt{ }

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Quantum Physics

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4 years ago
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I hope you find this information useful and interesting! Good luck!

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A baseball pitcher throws a ball across home plate. The ball travels 13.40m in 0.357s Determine the
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Answer: I'm not sure what it needs to be rounded to, but I got 37.53501401 m/s

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I hope this helps! :)

4 0
2 years ago
A toy car having mass m = 1.10 kg collides inelastically with a toy train of mass M = 3.55 kg. Before the collision, the toy tra
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Answer:

V_{ft}= 317 cm/s

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Explanation:

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P_i = P_f

Where:

P_i=M_cV_{ic} + M_tV_{it}

P_f = M_cV_{fc} + M_tV_{ft}

Now:

M_cV_{ic} + M_tV_{it} = M_cV_{fc} + M_tV_{ft}

Where M_c is the mass of the car, V_{ic} is the initial velocity of the car, M_t is the mass of train, V_{fc} is the final velocity of the car and V_{ft} is the final velocity of the train.

Replacing data:

(1.1 kg)(4.95 m/s) + (3.55 kg)(2.2 m/s) = (1.1 kg)(1.8 m/s) + (3.55 kg)V_{ft}

Solving for V_{ft}:

V_{ft}= 3.17 m/s

Changed to cm/s, we get:

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K_i = 22.06 J

And the final K is:

K_f = \frac{1}{2}M_cV_{fc}^2+\frac{1}{2}M_tV_{ft}^2

K_f = \frac{1}{2}(1.1)(1.8)^2+\frac{1}{2}(3.55)(3.17)^2

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Finally, the change in the total kinetic energy is:

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BaLLatris [955]
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We can see that the magnitude of the force is directly proportional to the charges. This means that when one of the charges is doubled, the magnitude of the electrostatic force will double as well, so the correct answer is
A) <span>The magnitude of the electrostatic force doubles</span>
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