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Vlad [161]
3 years ago
5

The data set shows the ages of people riding a bus.

Mathematics
1 answer:
likoan [24]3 years ago
4 0

Answer:

<u>The correct answer is B. 36</u>

Step-by-step explanation:

1. Let's review the information given for answering the question correctly:

Data set given:

18

36

11

45

36

19

14

18

36

2. What is the mode for this data set?

Let's recall that the Statistical Mode is the number that  is more frequently repeated in a group of numbers.  If no number is repeated, then there is no mode for the list or set.

In this specific set, we can notice that 18 is repeated two times and 36 is repeated three times. Therefore, the mode for this set of ages of people riding a bus is 36.

<u>The correct answer is B. 36</u>

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7x(3x2) and (7x3)x2​
Elis [28]

Answer:

what is the question

Step-by-step explanation:

6 0
3 years ago
Need help so much on Circle<br><br> Please help me for my geometry honors work please! Thank you
vichka [17]

Answer:

x = 95

Step-by-step explanation:

The total degree of a circle is 360. The twp arcs on each side of the parallel lines are equal.

Subtract 135 and 35 from your total

<em>360 - 135 - 35 = 190</em>

Divide your answer by 2

<em>190 ÷ 2 = 95</em>

6 0
2 years ago
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The table lists how poverty level income cutoffs​ (in dollars) for a family of four have changed over time. Use the midpoint for
frez [133]

The poverty level cutoff in 1987 to the nearest dollar  was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: \mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right).

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)

\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar  was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596

7 0
2 years ago
Find the difference 10 - ( – 25 )​
sergey [27]
There is no difference they are both negative numbers or we could say 25 is higher number then 10 but it negative
5 0
3 years ago
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Alexandra [31]

Answer:

12

Step-by-step explanation:

if x = 3

and y = 4

3 + 4 + 5 = 12

what grade is this

3 0
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