Both transportation and assignment problems are members of a category of lp problems called network flow problems
<h3>What is
network flow problems?</h3>
Network flow problems are a type of combinatorial optimization problem in which the input is a flow network (a graph with numerical capacities on its edges) and the goal is to construct a flow with numerical values on each edge that respect the capacity constraints and have incoming flow.
A company, for example, may want to ship packages from Los Angeles to New York City by using trucks to transport between intermediate cities. If the route connecting two cities only has one truck and each truck has a maximum load, the graph describing the transportation options will be a flow network.
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Answer and Explanation:
The computation is shown below
a. The economic order quantity is
= sqrt ((2 × annual demand × ordering cost) ÷ carrying cost)
= sqrt ((2 × 1,215 × $10) ÷ $75)
= 18 units
b) Average number of bags on hand is
= EOQ ÷ 2
= 18 ÷ 2
= 9
c) Orders per year is
= D ÷ EOQ
= 1215 ÷ 18
= 67.5
= 68
d) Total cost = Total carrying cost+ Total ordering cost
= (Q ÷ 2)H +(D ÷ Q)S
= (18 ÷ 2)75 + (1215 ÷ 18) × 10
= 675 + 675
= $1350
Answer:
Using Quantifiers: ¬∃x¬S(x)≡ ∀xS(x)
English Language: All drivers obey the speed limit
Explanation:
The domain is the set of all drivers i.e. the domain of drivers
Let S(x) be the predicate “x obeys the speed limit.”
The above statement can be written as ∃x¬S(x),
The negation is represented by ¬∃x¬S(x)≡ ∀xS(x)
In English Language, it is ->, all drivers obey the speed limit
Answer:
C) 42%; 11%
Explanation:
The total calories in one Planters NUT-rition Cranberry Almond Peanut bar =
- fats: 35 grams x 23% x 9 calories = 72.45 calories
- carbohydrates: 35 grams x 57% x 4 calories = 79.8 calories
- proteins: 35 grams x 14% x 4 calories = 19.6 calories
- total 171.85 calories
percent calories from fat = 72.45 calories / 171.85 calories = 0.4216 x 100 = 42.16% ≈ 42%
percent calories from protein = 19.6 calories / 171.85 calories = 0.1141 x 100 = 11.41% ≈ 11%