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3 years ago

NEED HELP ASAP PLEASE !!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Chemistry

2 answers:

MakcuM [25]3 years ago

8 0

A +1 ion https://quizlet.com/253790701/icy-spice-flash-cards/

sasho [114]3 years ago

7 0

Answer:

It will form a +1 ion

Explanation:

The electronic configuration tells you that this atom has only 1 electron on it's external level. In a chemical reaction the external electrons are the ones involved. In this case the Li atom will lose the electron that belongs to the 2s1 orbital to achieve stabilty. the electron has a negative charge so if the Li loses 1 electron it remains with 1 extra positive charge, therefor it will form an +1 ion

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What quantity measures the amount of space an object occupies?

mylen [45]

The answer would be volume

3 0

2 years ago

23• C=_____K what’s the answer 23 296 -250 123

UkoKoshka [18]

Kelvins = Celsius + 273

Kelvins = 23 + 273

answer = 296

5 0

3 years ago

The equilibrium constant for the reaction 2NO(g)+Br2(g)⥫⥬==2NOBr(g) is Kc=1.3×10−2 at 1000 K. At this temperature does the equil

o-na [289]

Answer :

The equilibrium favors NO and $Br_2$ .

(1) The value of equilibrium constant for this reaction is, 76.9

(2) The value of equilibrium constant for this reaction is, 8.77

Explanation:

The given chemical equation is:

$2NO(g)+Br_2(g)\rightarrow 2NOBr(g)$

The value of equilibrium constant for the above equation is $K_c=1.3\times 10^{-2}$ .

The value of $K_c$ that means equilibrium lies to the left side. Thus, the equilibrium favors NO and $Br_2$ .

We need to calculate the equilibrium constant for the given equation of above chemical equation, which is:

(1) $2NOBr(g)\rightarrow 2NO(g)+Br_2(g)$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{c_1}=\frac{1}{K_c}$

$K_{c_1}=\frac{1}{1.3\times 10^{-2}}=76.9$

Thus, the value of equilibrium constant for this reaction is, 76.9

(2) $NOBr(g)\rightarrow NO(g)+\frac{1}{2}Br_2(g)$

The equilibrium constant for the reverse reaction will be the reciprocal of the initial reaction.

If the equation is multiplied by a factor of '1/2', the equilibrium constant of the reverse reaction will be the 1/2 power of the equilibrium constant of initial reaction.

The value of equilibrium constant for reverse reaction is:

$K_{c_2}=(\frac{1}{K_c})^{1/2}$

$K_{c_2}=(\frac{1}{1.3\times 10^{-2}})^{1/2}=8.77$

Thus, the value of equilibrium constant for this reaction is, 8.77

7 0

4 years ago

Read 2 more answers

In the reaction 2Na + Cl2 → 2NaCl, the products are

Lisa [10]

During a reaction, there are reactants and products. Reactants are the elements that are being added. Products are the result of the reactants.

2Na + Cl2 are the reactants.

2NaCl is the Product.

I hope this helps!

8 0

3 years ago

A 5.22 × 10−3−mol sample of HY is dissolved in enough H2O to form 0.088 L of solution. If the pH of the solution is 2.37, what i

OleMash [197]

Answer:

3.07 × 10⁻⁴

Explanation:

Step 1: Calculate the concentration of H⁺

We will use the definition of pH.

$pH = -log [H^{+} ]\\\[ [H^{+} ] = antilog -pH = antilog -2.37 = 4.27 \times 10^{-3} M$