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ANEK [815]
3 years ago
13

what grade is learning What amount of thermal energy (heat) in joules required to raise the temperature of 25 grams of water fro

m 0 degrees C to 100 degrees C?
Chemistry
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:

10425 J are required

Explanation:

assuming that the water is entirely at liquid state at the beginning , the amount required is

Q= m*c*(T final - T initial)

where

m= mass of water = 25 g

T final = final temperature of water = 100°C

T initial= initial temperature of water = 0°C

c= specific heat capacities of water = 1 cal /g°C= 4.186 J/g°C ( we assume that is constant during the entire temperature range)

Q= heat required

therefore

Q= m*c*(T final - T initial)= 25 g * 4.186 J/g°C * (100°C- 0°C) = 10425 J

thus 10425 J are required

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