What is the volume of 2.10 moles of chlorine gas (Cl2) at 273 K and 1.00 atm?
1 answer:
Ideal gas law:
PV=nRT ⇒ V=nRT / P
P=pressure=1 atm
V=volume
n=number moles=2.10 moles
R=0,082 Atm l/ºK mol
T=temperature=273 K
V=(2.10 moles*0.082 (atm l)/º(K mol)*237ºK) / 1 atm=47.01 litres
47.1 L
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