Equilibrium of Non-Concurrent Forces Lab
1 answer:
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<h2>Answer</h2>
The volume will be <u>increased</u>
<h2>Explanation</h2>Look at the formula
If the mass increase the density will be increased because of their direct relationship. But in the case of constant mass. The volume increase the density will decrease because there is an inverse relationship exists between them. In the inverse relationship, the two objects perform differently. for example, if you are going to inflate the balloon, its volume will increase but density decrease
Answer:
The specific latent heat of ice is approximately 341 J/g
The correct option is;
b) 341 J/g
Explanation:
The given parameters are;
The mass of ice the pupil adds to the water, m₁ = 37 g
The initial temperature of the ice, T₁ = 0°C
The mass of the water to which the ice is added, m₂ = 100 g
The initial temperature of the water, T₂₁ = 30°C
The final temperature of the water and the melted ice, T₂₂ = 0°C
The specific heat capacity of the water, c₂ = 4.2 J/(g·°C)
By the principle of conservation of energy, we have;
The heat gained by the ice = The heat lost by the water = ΔQ₂
Given that the ice is only melted with no change in temperature, we have;
The heat gained by the ice = The latent heat needed for melting the ice
ΔQ₂ = m₂ × c₂ × (T₂₂ - T₂₁) = 100 × 4.2 × (0 - 30) = -12,600 J
The heat gained by the ice = m₁ ×
Where;
represents the specific latent heat of fusion of ice;
We have;
12,600 = 37 ×
= 12,600/37 = 340.54 J/g ≈ 341 J/g
The specific latent heat of fusion of ice = ≈ 341 J/g.