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3 years ago

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if an object's density is decreasing but its mass stays constant, what must be true of the object's volume?

1 answer:

astra-53 [7]3 years ago

8 0

<h2>Answer</h2>

The volume will be <u>increased</u>

<h2>Explanation</h2>

Look at the formula

$Density = Mass/Volume$

If the mass increase the density will be increased because of their direct relationship. But in the case of constant mass. The volume increase the density will decrease because there is an inverse relationship exists between them. In the inverse relationship, the two objects perform differently. for example, if you are going to inflate the balloon, its volume will increase but density decrease

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he measured flow rate of water through a 20 mm diameter pipe is 75 L/min. What is the average velocity (in m/s) of water flowing

Masteriza [31]

Answer:

Average velocity of water flow through the pipe = 3.98 m/s

Explanation:

Diameter of pipe = 20 mm

Discharge = 75 L/min

We know that

Discharge = Area x Velocity

$\texttt{Area of pipe}=\frac{\pi d^2}{4}=\frac{\pi \times (20\times 10^{-3})^2}{4}=3.14\times 10^{-4}m^2$

Discharge = 75 L/min

$=\frac{75\times 10^{-3}}{60}=1.25\times 10^{-3}m^3/s$

Substituting

$1.25\times 10^{-3}=3.14\times 10^{-4}\times V\\\\V=3.98m/s$

Average velocity of water flow through the pipe = 3.98 m/s

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grigory [225]

Answer:

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Gala2k [10]

Answer:

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Explanation:

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Read 2 more answers

what is the mass of vertical column of air that exerts pressure of 1 atm over a10m by 10m square surface

Oksana_A [137]

Answer:

$m=1.01\times 10^6\ kg$

Explanation:

Given that,

Pressure, P = 1 atm = 101325 Pa

Area of the square surface, A = 10² = 100 m²

We need to find the mass of vertical column of air. We know that, pressure is equal to the force acting per unit area. So,

$P=\dfrac{mg}{A}\\\\m=\dfrac{PA}{g}\\\\m=\dfrac{101325\times 10^2}{10}\\\\m=1.01\times 10^6\ kg$

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3 years ago