Answer:
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Explanation:
sdfgvfcdsertgyhbvcfxdsrftgh
Answer:
A reduction potential measures the tendency of a molecule to be reduced by taking up new electrons. ... Standard reduction potentials can be useful in determining the directionality of a reaction. The reduction potential of a given species can be considered to be the negative of the oxidation potential.
Explanation:
Answer:
c and d, are you supposed to check 3? or only 2?
Explanation:
Ionization equation for
is as follows.

s s s
Now, the expression for the solubility product is as follows.
![K_{sp} = [Ca^{2+}][SO^{2-}_{4}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BCa%5E%7B2%2B%7D%5D%5BSO%5E%7B2-%7D_%7B4%7D%5D)
= 
= 
As the concentration of
is given as 0.4 M.
So,
= 0.4 M
Putting the given values as follows.
![K_{sp} = [Ca^{2+}][SO^{2-}_{4}]](https://tex.z-dn.net/?f=K_%7Bsp%7D%20%3D%20%5BCa%5E%7B2%2B%7D%5D%5BSO%5E%7B2-%7D_%7B4%7D%5D)
![4.93 \times 10^{-5} = [Ca^{2+}] \times 0.4](https://tex.z-dn.net/?f=4.93%20%5Ctimes%2010%5E%7B-5%7D%20%3D%20%5BCa%5E%7B2%2B%7D%5D%20%5Ctimes%200.4)
= 12.325 \times 10^{-5}[/tex]
Hence, the solubility of
in
is
.
Therefore, solubility of
in g/ml as follows.

= 0.0167 g/L
Thus, we can conclude that solubility of
is 0.0167 g/L.