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Vilka [71]
3 years ago
5

How many oxygen atoms are in 7.90 g of Al2(SO4)3?

Chemistry
1 answer:
Zanzabum3 years ago
6 0
The answer to your question is 55,600,000,000,000,000,000,000atoms
You might be interested in
How many atoms of carbon are in 6.00g of carbon?(Mm of carbon is<br> 12g/mol)
xenn [34]
<h3>Answer:</h3>

3.01 × 10²³ atoms C

<h3>General Formulas and Concepts:</h3>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right
<h3>Explanation:</h3>

<u>Step 1: Define</u>

6.00 g C

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

<u>Step 3: Convert</u>

<u />6.00 \ g \ C(\frac{1 \ mol \ C}{12.01 \ g \ C} )(\frac{6.022 \cdot 10^{23} \ atoms \ C}{1 \ mol \ C} ) = 3.00849 × 10²³ atoms C

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.00849 × 10²³ atoms C ≈ 3.01 × 10²³ atoms C

5 0
3 years ago
49 points! Will mark brainliest!
Sholpan [36]

1. Given the following equation: N2 (g) + 3 H2 (g) ↔ 2NH3 (g) ΔH = -92 kJ/mol

a. this reaction is exothermic as ΔH is -ve

b. the equilibrium will shift 2 the left if nitrogen gas is removed

c. the equilibrium shift 2 the right if the temperature is lowered

d. the equilibrium shift 2 the left if ammonia (NH3) is added

e. principle of thermodynamic potential or Gibbs energy is used to answer B-D

8 0
3 years ago
Read 2 more answers
The combustion of magnesium creates so much energy so quickly that it is hard to measure its enthalpy directly using a simple ca
riadik2000 [5.3K]
I believe your answer is: What is the enthalpy of formation of magnesium oxide?
Hope this helps! :)
6 0
3 years ago
Read 2 more answers
What is the concentration of x2??? in a 0.150 m solution of the diprotic acid h2x? for h2x, ka1=4.5??10???6 and ka2=1.2??10???11
lutik1710 [3]
The first dissociation for H2X:
                        H2X +H2O ↔ HX + H3O
initial                0.15                     0      0
change             -X                     +X      +X
at equlibrium 0.15-X                  X        X
because Ka1 is small we can assume neglect x in H2X concentration
     Ka1      = [HX][H3O]/[H2X]
4.5x10^-6 =( X )(X) / (0.15)
X = √(4.5x10^-6*0.15) 
∴X = 8.2 x 10-4 m
∴[HX] & [H3O] = 8.2x10^-4
the second dissociation of H2X
        HX + H2O↔ X^2 + H3O
    8.2x10^-4          Y         8.2x10^-4
Ka2 for Hx = 1.2x10^-11
Ka2       = [X2][H3O]/[HX]
1.2x10^-11= y (8.2x10^-4)*(8.2x10^-4)
∴y = 1.78x10^-5
∴[X^2] = 1.78x10^-5 m


4 0
3 years ago
How can you force a solid compound to the bottom of a melting point capillary? a. tap the closed endb. tap the open endc. use a
snow_lady [41]

Answer: option A. tap the closed end

Explanation:

3 0
3 years ago
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