An ionic compound can be formed through the existence of valency above the compound e.g NH4 which have +3 as it's ionic charge
<u>Answer:</u> The value of <em>i</em> is 1.4 and 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.
<u>Explanation:</u>
The equation used to calculate the Vant' Hoff factor in dissociation follows:
where,
= degree of dissociation = 40% = 0.40
i = Vant' Hoff factor
n = number of ions dissociated = 2
Putting values in above equation, we get:
The equation used to calculate the degee of dissociation follows:
Total number of particles taken = 100
Degree of dissociation = 40% = 0.40
Putting values in above equation, we get:
This means that 40 particles are dissociated and 60 particles remain undissociated in the solution.
Hence, 40% dissociation of 100 particles of zinc sulfate will yield 60 undissociated particles.
A: BE has more ionization energy than LI
B: CA has more ionization energy than BA.
C: NA has more ionization energy than K
D: AR has more ionization energy than P
E: CI has a more ionization energy than SI
F: LI has more ionization energy than K
If any of these are wrong feel free to correct me in the comments.
Answer:
a. equal to
Explanation:
The <em>osmotic pressure</em> is calculated by the formula:
π = <em>i</em> * M * R * T
Where π is the osmotic pressure, M is the concentration, R is a constant, T is temperature and <em>i</em> is the van't Hoff's factor (the number of ions a compound forms when dissolved in water,<u> for both NaCl and KBr is 2</u>).
Because R is always the same, and <u>Temperature and Concentration are equal between the two solutions</u>, the osmotic pressure of both solutions are also equal.
