Answer:
Because heat causes alcohol to volatilize, instead of burning it.
The combustion is not fulfilled since this is detached from the surface of the banknote that would be the necessary product to burn, in addition to considering that the necessary temperature is not reached
Explanation:
When water and alcohol are joined, they form a solution with high evaporation power, plus alcohol that has a higher degree of volatility than water, this is how these liquids are not retained on the surface of the banknote with heat and they are not it burns.
Given what we know, we can confirm that when an excited electron spontaneously emits a photon, the energy released is electromagnetic energy.
<h3>What is a Photon and what energy does it release when being emitted?</h3>
- A photon is a particle.
- This means that it is one of the smallest forms of matter that we can study.
- Photons form electromagnetic fields.
- Therefore, when being emitted by an electron, photons release electromagnetic energy.
Therefore, we can confirm that when an excited electron spontaneously emits a photon, the energy released is electromagnetic energy due to the properties of the photon being emitted.
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229.25 mL of isopropyl alcohol
425.75 mL of water
Explanation:
Knowing that the solution have a 35.0 % (v/v) isopropyl alcohol in water, we can calculate the volume of each component as following.
volume of isopropyl alcohol = (35/100) × solution volume
volume of isopropyl alcohol = 0.35 × 655 mL = 229.25 mL
Now, knowing the volume of isopropyl alcohol we can determine the volume of water.
volume of the solution = volume of isopropyl alcohol + volume of water
volume of water = volume of the solution - volume of isopropyl alcohol
volume of water = 655 mL - 229.25 mL = 425.75 mL
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percent by volume concentration
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Answer:
Thus, the radius of the helium atom in nanometers is - 0.031 nm
Explanation:
Given that:-
The radius of the helium atom = 31 pm
Considering the conversion of length in pm to the length in nm as:-
1 pm = 0.001 nm
So,
Applying the above conversion factor in the radius of helium atom as:-
Radius = 
nm = 0.031 nm
<u>Thus, the radius of the helium atom in nanometers is - 0.031 nm</u>
