Answer:
I believe the answer would be: D
an independent variable that is affected by the other
experimental variable
Correct me if im wrong
Explanation:
<span>
</span> so the only one that is currently unbalanced is the oxygen there is two on the left and three on the right side If we add a two in front of the PbOPbS + O2 --> 2PbO + SO2Now Pb is unbalanced as well to balance I'll put a 2 in front of the PbS2PbS + O2 --> 2PbO + SO2Pb is balanced but S isn't anymore so we will put a 2 in front of the SO22PbS + O2 --> 2PbO + 2SO2Now Pb is balanced and S is balanced only O is unbalanced We have 2 on the left and 6 on the rightTo balance we need 6 oxygen on the left6/2=32PbS + 3O2 --> 2PbO + 2SO2 That is the balanced equation
Answer:
The ball hit with 12 N
Explanation:
acceleration = Force/ mass
If masses of balls are the same, then more the force - more acceleration.
12N more than 8N,
so the ball that hits Stacy accelerate faster.
Answer:
0.05 mL
Explanation:
Initially, we have a concentrated solution of NaOH, to which we will add water to get a dilute one. To calculate the volume of the initial solution that we have to measure, we can use the dilution rule:
C₁ × V₁ = C₂ × V₂
where,
C₁ is the initial concentration (50% w/w; ρ = 1.52 g/mL)
V₁ is the initial volume
C₂ is the final concentration (0.1 M)
V₂ is the final volume (10 mL)
First, we have to calculate the weight/volume percentage and then the molarity of the first solution.
Now, we can apply the dilution rule.
Answer:
49.4 g Solution
Explanation:
There is some info missing. I think this is the original question.
<em>A chemistry student needs 20.0g of acetic acid for an experiment. He has 400.g available of a 40.5 % w/w solution of acetic acid in acetone. </em>
<em>
Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to 3 significant digits.</em>
<em />
We have 400 g of solution and there are 40.5 g of solute (acetic acid) per 100 grams of solution. We can use this info to find the mass of acetic acid in the solution.
Since we only need 20.0 g of acetic acid, there is enough of it in the solution. The mass of solution that contains 20.0 g of solute is: