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Vinil7 [7]
3 years ago
6

The boom of a fire truck raises a fireman (and his equipment – total weight 280 lbs) 60 ft into the air to fight a building fire

. (a) Showing all your work and using unity conversion ratios, calculate the work done by the boom on the fireman in units of Btu. (b) If the useful power supplied by the boom to lift the fireman is 3.50 hp, estimate how long it takes to lift the fireman
Physics
1 answer:
Simora [160]3 years ago
6 0

Explanation:

Given that,

Weight = 280 lbs

Height = 60 ft

Power = 3.50 hp

(a). We need to calculate the work done by the boom on the fireman

Using formula of work done

Work\ done =Weight\ \times height

W'=W\times h

Put the value into the formula

W'=280\times60

W'= 16800 ftlbf

W'=\dfrac{16800}{778.169}

W'=21.59\ Btu

The work done by the boom is 21.59 Btu.

(b). We know that,

1 hp = 550 ft lbf

So, P = 3.50\times550

P=1925\ ft-lbf/s

We need to calculate the time

Using formula of time

t = \dfrac{W}{P}

Put the value into the formula

t=\dfrac{16800}{1925}

t =8.7\ sec

The time is 8.7 sec.

Hence, This is the required solution.

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A train of mass 3.3 × 10^6 kg is moving at a constant speed up a slope inclined at an angle of 0.64°
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Answer:

C. 39 m/s

Explanation:

First we need to calculate the total force required to move the train along the inclined plane. So, it is clear that the work done will be equal to the component of the weight that is parallel to the inclined plane, because there is no frictional force present:

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F = (3.3 x 10⁶ kg)(9.8 m/s²)Sin 0.64°

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