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Lostsunrise [7]
3 years ago
11

What is self-esteem? An individual's desire to grow An individual's sense of self worth An individual's drive to fulfill biologi

cal needs An individual's knowledge about him or herself
Physics
2 answers:
mariarad [96]3 years ago
6 0
An individuals sense of self worth.
Eddi Din [679]3 years ago
3 0

Answer:

An individual's sense of self worth

Explanation:

Self-esteem is the quality that belongs to the individual who is satisfied with his or her identity, that is, a person who has confidence and values himself. In psychology, self-esteem is a subjective assessment that a given individual makes of himself. In this case, characteristics such as dignity, respect and trust are present in that person's personality.

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Olin [163]

Answer:

Fluorescent Lights

Explanation:

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3 years ago
A cement truck of mass 14,000 kg moving 10m/s slams into a wall and comes to a halt in .2s. What is the force of impact on the t
skelet666 [1.2K]

And it’s x10 is 100000

6 0
3 years ago
Calculate the current flowing if a charge of 36 kilocoulombs flows in 1 hour.
o-na [289]

Answer:

Current = 10 Amperes.

Explanation:

Given the following dat;

Quantity of charge, Q = 36 kilocoulombs (KC) = 36 * 1000 = 36000C

Time = 1 hour to seconds = 60*60 = 3600 seconds

To find the current;

Quantity of charge = current * time

Substituting in the equation

36000 = current * 3600

Current = 36000/3600

Current = 10 Amperes.

6 0
3 years ago
un futbolista patea una pelota que se encuentra en el pasto con un angulo de 30° (medido desde la horizontal) con la intención d
Rus_ich [418]

Answer:

i dont really know what it is

8 0
3 years ago
(a) Calculate the force (in N) needed to bring a 1100 kg car to rest from a speed of 85.0 km/h in a distance of 125 m (a fairly
nasty-shy [4]

(a) -2451 N

We can start by calculating the acceleration of the car. We have:

u=85.0 km/h = 23.6 m/s is the initial velocity

v = 0 is the final velocity of the car

d = 125 m is the stopping distance

So we can use the following equation

v^2 - u^2 = 2ad

To find the acceleration of the car, a:

a=\frac{v^2-u^2}{2d}=\frac{0-(23.6 m/s)^2}{2(125 m)}=-2.23 m/s^2

Now we can use Newton's second Law:

F = ma

where m = 1100 kg to find the force exerted on the car in order to stop it; we find:

F=(1100 kg)(-2.23 m/s^2)=-2451 N

and the negative sign means the force is in the opposite direction to the motion of the car.

(b) -1.53\cdot 10^5 N

We can use again the equation

v^2 - u^2 = 2ad

To find the acceleration of the car. This time we have

u=85.0 km/h = 23.6 m/s is the initial velocity

v = 0 is the final velocity of the car

d = 2.0 m is the stopping distance

Substituting and solving for a,

a=\frac{v^2-u^2}{2d}=\frac{0-(23.6 m/s)^2}{2(2 m)}=-139.2 m/s^2

So now we can find the force exerted on the car by using again Newton's second law:

F=ma=(1100 kg)(-139.2 m/s^2)=-1.53\cdot 10^5 N

As we can see, the force is much stronger than the force exerted in part a).

8 0
3 years ago
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