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natulia [17]
2 years ago
13

According to the record of the registrar's office at a state university, 35% of the students arefreshman, 25% are sophomore, 16%

are junior, and the rest are senior. Among the freshmen,sophomores, juniors, and seniors, the portion of students who live in the dormitory are,respectively, 80%, 60%, 30%, and 20%. What is the probability that a randomly selected studentis a freshman who lives in a dormitory?
A) 0.28
B) 0.32
C) 0.52
D) 0.38
Mathematics
1 answer:
Art [367]2 years ago
6 0

Answer:

the probability is 0.28

Step-by-step explanation:

using Bayes's theorem

P(A|B)=P(A∩B)/P(B)

where

P(A∩B) = probability that events A and B happen

P(A|B) = probability that event A happen if B already happened

P(B)= probability of event B

therefore

P(A∩B)=P(A|B)*P(B)

if event A= selection of a student that lives in a dormitory  and event B = selection of a freshmen student

P(A|B) = 0.8 (live in a dormitory knowing that is a freshmen student )

P(B) = 0.35 (freshmen student)

P(A∩B)=P(A|B)*P(B) = 0.8* 0.35 =0.28

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Step-by-step explanation:

Simplifying

2.1x + -5.7 = 3.9(4.3 + -1.8x)

Reorder the terms:

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Solving for variable 'x'.

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Add '7.02x' to each side of the equation.

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Combine like terms: 2.1x + 7.02x = 9.12x

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Combine like terms: -7.02x + 7.02x = 0.00

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Hello, I am papaguy


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Please note this is information you can use do not copy and paste.


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