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attashe74 [19]
3 years ago
5

What are the products formed when ethane burns in excess oxygen?

Chemistry
1 answer:
Neporo4naja [7]3 years ago
3 0
2 C2H6 + 7 O2 -> 4CO2 + 6 H2O 
<span>so the products are carbondioxide & water vapour</span>
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# of protons = 48 <br><br> Cadmium <br> Titanium <br> Oxygen <br> Krypton
Dafna11 [192]

Answer:

Cadmium +p= 48

Titanium p=22

Oxygen p=8

Krypton p=36

So the answer is Cadmium which has #48 protons

Explanation:

7 0
2 years ago
How can you tell if a electron configuration is ground state or excited state?
scZoUnD [109]
An excited state refers to an atom with electrons at a higher energy level. More than necessary and a ground state is when all atom's electrons are in their lowest orbital possible
8 0
3 years ago
what is the specific heat of a substance if 300 j are required to raise the temperature of a 267-g sample by 12 degrees c
slava [35]

Answer : The specific heat of the substance is 0.0936 J/g °C

Explanation :

The amount of heat Q can be calculated using following formula.

Q = m \times C \times \bigtriangleup T

Where Q is the amount of heat required = 300 J

m is the mass of the substance = 267 g

ΔT is the change in temperature = 12°C

C is the specific heat of the substance.

We want to solve for C, so the equation for Q is modified as follows.

C = \frac{Q}{m \times \bigtriangleup T}

Let us plug in the values in above equation.

C = \frac{300J}{267g \times 12 C}

C = \frac{300J}{3204 g C}

C = 0.0936 J/g °C

The specific heat of the substance is 0.0936 J/g°C

3 0
3 years ago
which two will help you measure how different colors absorb the energy in sunlight is it beaker or thermometer
KATRIN_1 [288]
Beaker does thermometer measures the thermal energy in the air
6 0
3 years ago
Write balanced equations for the following reactions
Arte-miy333 [17]

Answer:

See explanation

Explanation:

The shorthand nuclear reaction equations have been given; the first particle in the parentheses is a reactant particle while the second particle is a product particle. These can now be rewritten as the longhand equations as follows;

238/92U + 4/2 He -------> 241/94Pu + 1/0 n

238/92U + 4/2 He ------> 241/94Pu + 1/0 n

14/7N + 4/2 He------> 17/8O + 1/1 p

56/26Fe + 2 4/2 He----> 60/29Cu + 4/2 He

4 0
3 years ago
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