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ehidna [41]
3 years ago
14

Consider a fully-clamped circular diaphragm poly-Si with a radius of 250 μm and a thickness of 4 μm. Assume that Young’s modulus

is 130 GPa and Poisson’s ratio is 0.3. A uniform pressure of 20 kPa is applied.
(a) What is the stress at the center of the diaphragm?
(b) What is the radial stress at the fully-clamped edge of the diaphragm?
(c) What is the transverse stress at the fully-clamped edge of the diaphragm?
(d) What is the amount of deflection at the center of the diaphragm?

Engineering
1 answer:
Alina [70]3 years ago
4 0

Answer:

Explanation:

find attached the solution to the question

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State the mathematical expression to define the availability of equipment over a specified time and operational availability?
Gelneren [198K]

Answer:

Availability=\dfrac{Up\ time}{Down\ time+Up\ time}

Explanation:

Availability:

  It define as the probability of system which perform desired task before showing any failure .

The availability can be define as follows

 Availability=\dfrac{Up\ time}{Down\ time+Up\ time}

Or we can say that

Availability=\dfrac{Up\ time}{total\ time}

Availability can also be express as

 Availability=\dfrac{MTBF}{MTBF+MTTR}

Where MTBF is the mean time between two failure.

MTTR is the mean time to repair.

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Risks in driving never begins with yourself, but with other drivers who take risks.
Ymorist [56]

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2 years ago
A house is losing heat at a rate of 1700 kJ/h per °C temperature difference between the indoor and the outdoor temperatures. Exp
Furkat [3]

Answer:

1700kJ/h.K

944.4kJ/h.R

944.4kJ/h.°F

Explanation:

Conversions for different temperature units are below:

1K = 1°C + 273K

1R = T(K) * 1.8

= (1°C + 273) * 1.8

1°F = (1°C * 1.8) + 32

Q/delta T = 1700kJ/h.°C

T (K) = 1700kJ/h.°C

= 1700kJ/K

T (R) = 1700kJ/h.°C

= 1700kJ/h.°C * 1°C/1.8R

= 944.4kJ/h.R

T (°F) = 1700kJ/h.°C

= 1700kJ/h.°C * 1°C/1.8°F

= 944.4kJ/h.°F

Note that arithmetic operations like subtraction and addition of values do not change or affect the value of a change in temperature (delta T) hence, the arithmetic operations are not reflected in the conversion. Illustration: 5°C - 3°C

= 2°C

(273+5) - (273+3)

= 2 K

5 0
4 years ago
Why will screws never replace nails​
cupoosta [38]

Answer:

because people have different opinions on nails and screws

Explanation:

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4 years ago
A spring-mass-damper instrument is employed for acceleration measurements. The spring constant is 12000 N/m. The mass is 5 g. Th
shepuryov [24]

Answer:

a) 246.56 Hz

b) 203.313 Hz

c) Add more springs

Explanation:

Spring constant = 12000 N/m

mass = 5g = 5 * 10^-3 kg

damping ratio = 0.4

<u>a) Calculate Natural frequency </u>

Wn = √k/m = \sqrt{12000 /  5*10^{-3}  }

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W / Wn = 0.8246

therefore Bandwidth ( W ) = Wn * 0.8246 = 246.56 * 0.8246 = 203.313 Hz

C ) To increase the bandwidth we have to add more springs

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3 years ago
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