Consider a fully-clamped circular diaphragm poly-Si with a radius of 250 μm and a thickness of 4 μm. Assume that Young’s modulus
is 130 GPa and Poisson’s ratio is 0.3. A uniform pressure of 20 kPa is applied.
(a) What is the stress at the center of the diaphragm?
(b) What is the radial stress at the fully-clamped edge of the diaphragm?
(c) What is the transverse stress at the fully-clamped edge of the diaphragm?
(d) What is the amount of deflection at the center of the diaphragm?
(a) What is the stress at the center of the diaphragm?
(b) What is the radial stress at the fully-clamped edge of the diaphragm?
(c) What is the transverse stress at the fully-clamped edge of the diaphragm?
(d) What is the amount of deflection at the center of the diaphragm?
1 answer:
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Answer:
radius = 9.1 × m
Explanation:
given data
applied load = 5560 N
flexural strength = 105 MPa
separation between the support = 45 mm
solution
we apply here minimum radius formula that is
radius = .................1
here F is applied load and is length
put here value and we get
radius =
solve it we get
radius = 9.1 × m
1)
2) 8.418
Explanation:
1)
The two components of the velocity field in x and y for the field in this problem are:
The x-component and y-component of the acceleration field can be found using the following equations:
The derivatives in this problem are:
Substituting, we find:
And
2)
In this part of the problem, we want to find the acceleration at the point
(x,y) = (-1,5)
So we have
x = -1
y = 5
First of all, we substitute these values of x and y into the expression for the components of the acceleration field:
And so we find:
And finally, we find the magnitude of the acceleration simply by applying Pythagorean's theorem: