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Molodets [167]
4 years ago
13

Calculate the approximate mass of the steel pipe. Length of pipe = 4m. Inside radius =130mm. Outside radius = 150mm

Engineering
1 answer:
Thepotemich [5.8K]4 years ago
6 0

Answer:

555.936 kg

Explanation:

h = Length of pipe = 4 m

r = Inside radius =130 mm

R = Outside radius = 150mm

Volume of the cylinder

v = πR²h - πr²h

⇒v = πh(R²-r²)

⇒v = π4(0.15²-0.13²)

⇒v = 0.0704 m³

Density of steel varies between 7,750 and 8,050 kg/m³

So, let us take the average of the two values so we get density of steel as 7900 kg/m³ as the exact density is not given

Density

\rho=\frac{m}{v}\\\Rightarrow m=\rho \times v\\\Rightarrow m=7900\times 0.704\\\Rightarrow m= 555.936\ kg

So, approximate mass of the steel pipe is 555.936 kg

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On the first statistics exam, the coefficient of determination between the hours studied and the grade earned was 80%. The stand
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Answer:

\left[\begin{array}{ccccc}&DF&SS&MS&F\\Regression&1&7200&7200&72\\Error&18&1800&100\\total&19&900\end{array}\right]

Explanation:

Sample size, n=20

Degrees of freedom is 1

Number of degrees of freedom for error is n-2 hence 20-2=18

Total number of degrees of freedom is 18+1=19

Standard error estimate is s_{y-x}=\sqrt {\frac {SSE}{n-2}}

Here, SSE=(n-2)s_{y-x}^{2}=(20-2)(10)^{2}=1800

Coefficient of determination r^{2}=\frac {SSE}{SS total}

Here, SSR=r^{2}(SSR+SSE)

SSR=\frac {r^{2}}{1-r^{2}} SSE=\frac {0.8}{1-0.8}(1800)=7200

The total sum of squares is

SS total=SSR+SSE=7200+1800=9000

MSR=SSR=7200

MSE=\frac {SSE}{n-2}=\frac {1800}{20-2}=100

F value is given by

F=\frac {MSR}{MSE}=\frac {7200}{100}=100

The ANOVA table is then  

\left[\begin{array}{ccccc}&DF&SS&MS&F\\Regression&1&7200&7200&72\\Error&18&1800&100\\total&19&900\end{array}\right]

4 0
4 years ago
Problem 4 You are designing a circuit to drive LED1, using the following circuit. The datasheet for the LED specifies that VF =
HACTEHA [7]

Answer:

a) I_LED= 1/6 A  b) Vf= 2.5V

Explanation:

Consider circuit in the attachment.

a) We will simplify current source in paraller with resistor to a voltage source in series with a resistor(see attachment 2)

Solving the circuit in attachment 2 using mesh analysis

-9+2I1+4(I1-I2)-4+2I1=0

8I1 - 4I2= 13 ............... eq 1

4+4(I2-I1)+ I2 + 2=0

4I1- 5I2 = 6 ............ eq 2

I1= 41/24 ;  I2 = 1/6; I2= I_LED

b) Solving the circuit in attachment 2 again, this time I2=0

8I1 - 4I2= 13

8I1- 4(0)=13

I1= 13/8

Vf= 4(I1- I2) -4

I2=I_LED=0

Vf= 2.5 V

4 0
4 years ago
Vehicles begin arriving at an amusement park 1 hour before the park opens, at a rale of four vehicles per minute. The gale to th
Alina [70]

Answer:

a) ≈ 30 mins

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Explanation:

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attached below is a detailed solution of the given problems above

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3 years ago
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Answer:

It serves as a guarantee that the contractor who wins the bid will honor the terms of the bid after the contract is signed.

Explanation:

A bid bond is a type of construction bond that protects the obligee in a  construction bidding process.

A bid bond typically involves three parties:

The obligee; the owner or developer of the construction project under bid. The principal; the bidder or proposed contractor.

The surety; the agency that issues the bid bond to the principal example insurance company or bank.

A bid bond generally serves as a guarantee that the contractor who wins the bid will honor the terms of the bid after the contract is signed.

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Answer:

only A

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