Answer:
248.756 mV
49.7265 µA
Explanation:
The Thevenin equivalent source at one terminal of the bridge is ...
voltage: (100 V)(1000/(1000 +1000) = 50 V
impedance: 1000 || 1000 = (1000)(1000)/(1000 +1000) = 500 Ω
The Thevenin equivalent source at the other terminal of the bridge is ...
voltage = (100 V)(1010/(1000 +1010) = 100(101/201) ≈ 50 50/201 V
impedance: 1000 || 1010 = (1000)(1010)/(1000 +1010) = 502 98/201 Ω
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The open-circuit voltage is the difference between these terminal voltages:
(50 50/201) -(50) = 50/201 V ≈ 0.248756 V . . . . open-circuit voltage
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The current that would flow is given by the open-circuit voltage divided by the sum of the source resistance and the load resistance:
(50/201 V)/(500 +502 98/201 +4000) = 1/20110 A ≈ 49.7265 µA
Answer:
improper imput validation
Explanation:
Answer:
Explanation:
effective delay = delay when no traffic x 
effective delay = 
Answer:
work which is required to move an electron from the positive terminal to the negative terminal is
-4μJ
W = -4μJ
Explanation:
Work required to move the charge
W = qΔV
initial point V₁ = 150V
Final point V₂ = -50V
W = q(V₂ -V₁)
= 20 × 10⁹(-50 - 150)
W = -4μJ
work which is required to move an electron from the positive terminal to the negative terminal is
-4μJ
