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3 years ago

BIG POINTS AND WILL GIVE BRAINLIEST! Answer all 5 please or I can’t give brainliest and might report!

Engineering

1 answer:

sergiy2304 [10]3 years ago

8 0

Answer:

1. Prokaryotes do have their genomic DNA concentrated and localized to a small area within the cell (nucleoid region). So it's not entirely accurate to say that prokaryotes don't have a nucleus. The cell can release DNAses into the cytoplasm to degrade viral DNA, with reduced risk of degrading it's own DNA.

2. A bioengineer would use the principles of mass and heat transfer to address a problem in human healthy by using mass and heat to solve problems in human health.

3. The key areas of controversy related to genetically modified food (GM food or GMO food) are whether such food should be labeled, the role of government regulators, the objectivity of scientific research and publication, the effect of genetically modified crops on health and the environment,

4. Biomaterial is an important part of bioengineering is because it plays a critical role in medicine today to restore function and facilitate healing for people after injury. These may be natural or synthetic and are used in medical to support, enhance, or replace damaged tissue.

5. Ethical issues that arise from modern biotechnologies include the availability and use of privileged information, potential for ecological harm, access to new drugs and treatments, and the idea of interfering with nature. Applications include agriculture and health care.

hope this helps

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Explanation:

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A cylindrical specimen of a metal alloy 45.8 mm long and 9.72 mm in diameter is stressed in tension. A true stress of 378 MPa ca

Sliva [168]

Answer:

390.242 MPa

Explanation:

Attached is the full solution.

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3 years ago

The lift on a spinning circular cylinder in a freestream with a velocity of 30 m/s and at standard sea level conditions is 6 N/m

Evgesh-ka [11]

Answer:

The circulation around the cylinder is 0.163 $\frac{m^{2} }{s}$

Explanation:

Given :

Velocity of spinning cylinder $v = 30$ $\frac{m}{s}$

Sea level density $\rho = 1.23$ $\frac{kg}{m^{3} }$

Sea level span $L = 6$ $\frac{N}{m}$

Lift per unit circulation is given by,

$L = \rho v c$

Where $c =$ circulation around cylinder

$c = \frac{L}{\rho v}$

$c = \frac{6}{1.23 \times 30}$

$c = 0.163$ $\frac{m^{2} }{s}$

Therefore, the circulation around the cylinder is 0.163 $\frac{m^{2} }{s}$

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4 years ago

Sarah is developing a Risk Assessment for her organization. She is asking each department head how long can they be without thei

Natali [406]

Answer:

Sarah is asking each department head how long they can be without their primary system. Sarah is trying to determine the Recovery Time Objective (RTO) as this is the duration of time within which the primary system must be restored after the disruption.

Recovery Point Objective is basically to determine the age of restoration or recovery point.

Business recovery and technical recovery requirements are to assess the requirements to recover by Business or technically.

Hence, Recovery Time Objective (RTO) is the correct answer.

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3 years ago

11. When selecting a route for a long trip, you should

mamaluj [8]

Answer:

Explanation:

i think do kill me if im wrong

6 0

3 years ago

Read 2 more answers

A cylinder fitted with a frictionless piston contains 2 kg of R-134a at 3.5 bar and 100 C. The cylinder is now cooled so that th

inna [77]

Answer:

The answer to the question is

The heat transferred in the process is -274.645 kJ

Explanation:

To solve the question, we list out the variables thus

R-134a = Tetrafluoroethane

Intitial Temperaturte t₁ = 100 °C

Initial pressure = 3.5 bar = 350 kPa

For closed system we have m₁ = m₂ = m

ΔU = m×(u₂ - u₁) = ₁Q₂ -₁W₂

For constant pressure process we have

Work done = W = $\int\limits^a_b P \, dV$ = P×ΔV = P × (V₂ - V₁) = P×m×(v₂ - v₁)

From the tables we have

State 1 we have h₁ = (490.48 +489.52)/2 = 490 kJ/kg

State 2 gives h₂ = 206.75 + 0.75 × 194.57= 352.6775 kJ/kg

Therefore Q₁₂ = m×(u₂ - u₁) + W₁₂ = m × (u₂ - u₁) + P×m×(v₂ - v₁)

= m×(h₂ - h₁) = 2.0 kg × (352.6775 kJ/kg - 490 kJ/kg) =-274.645 kJ

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3 years ago