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SOVA2 [1]
3 years ago
8

How does an atom change if all of its electrons are removed?

Chemistry
2 answers:
amm18123 years ago
6 0
Adding or removing<span> them from the nucleus </span>does<span> not</span>change<span> the electrical charge of the nucleus.</span>
Dafna1 [17]3 years ago
3 0
If all the electrons are removed, the atom becomes a cation because it is a negative charged atom.
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2B + 3H2 2BH3<br> How many moles of BH3 are synthesized when 27.0 moles of H2 completely react?
densk [106]

Answer:

fa o poză te rog frumos ca nu stiu ce ex este

3 0
3 years ago
What's the formula equation for the reaction that occurred between the barium chloride solution , BaCl2 (aq), and the sodium sul
Solnce55 [7]
The balanced equation is:

BaCl2 (aq) + Na2SO4 (aq) ----> BaSO4(s)+ 2 NaCl(aq)

This is a double replacement reaction.

The reactants are:

a) BaCl2: barium chloride, a ionic compound, therefore soluble in water,

b) Na2SO4: sodium sulfate, another ionic compound, therefore also soluble in water.

The products are:

c) BaSO4: barium sulfate, a solid not soluble in water which precipitates.

d) NaCl: sodium chloride, an ionic compound, therefore soluble in water.
4 0
3 years ago
Solubility of a salt that has a general formula M3X (where M is the cation and X is the anion) is 0.0283 g/L of the solution. Th
egoroff_w [7]

ksp = 7.003 \times  {10}^{ - 16}  {mol}^{4}  {dm}^{ - 12}

6 0
3 years ago
Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?
Rufina [12.5K]
Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
C = 0.25 mg
t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

=> k = ln {Co / C} / t =  ln {2.00mg / 0.25mg} / 4.65 hr = 0.44719

2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

=> -kt = ln (1/2) => kt = ln(2) => t = ln (2) / k

t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr
6 0
3 years ago
Phosphorus trichloride gas and chlorine gas react to form phosphorus pentachloride gas: PCl3(g)+Cl2(g)⇌PCl5(g). A 7.5-L gas vess
Tpy6a [65]

Answer:

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

Explanation:

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The relation of K_c\& K_p is given by:

K_p=K_c(RT)^{\Delta n_g}

K_p= Equilibrium constant in terms of partial pressure.=98.1

K_c= Equilibrium constant in terms of concentration  =?

T = temperature at which the equilibrium reaction is taking place.

R = universal gas constant

\Delta n_g = Difference between gaseous moles on product side and reactant side=n_{g,p}-n_{g.r}=1-2=-1

98.1=K_c(RT)^{-1}

98.1 =\frac{K_c}{RT}

K_c=98.1\times 0.0821 L atm/mol K\times 450 K=3,624.30=3.6243\times 10^{3}

The equilibrium constant in terms of concentration that is, K_c=3.6243\times 10^{3} .

5 0
3 years ago
Read 2 more answers
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