Question

A student fires a cannonball vertically upwards. The cannonball returns to the

Answer 1

Answer:

(a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

Explanation:

Given that,

Time = 4.60 s

We need to calculate the initial velocity

Using equation of motion

$v=u-gt$

Put the value into the formula

$0=u-9.8\times4.60$

$u=45.0\ m/s$

We need to calculate the distance

Using formula of distance

$d=v\times t$

Put the value into the formula

$d=45\times4.60$

$d=207\ m$

We need to calculate the maximum height

Using equation of motion

$v^2=u^2-2gh$

Put the value into the formula

$0=(45.0)^2-2\times9.8\times h$

$h=\dfrac{(45.0)^2}{2\times9.8}$

$h=103.3\ m$

Hence, (a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m